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joja [24]
3 years ago
14

**ANSWER NEEDED FAST** (giving brainliest) Heres the question ;; In a Honeycomb Path puzzle, the goal is to fill every empty hex

agon (⬡) with a number so that a path of consecutive numbers crosses every hexagon. Consecutive numbers come one after another. For example 11, 12, and 13 are consecutive. What numbers should fill the center row of the honeycomb below from left to right?

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
4 0

Answer:

19, 18, 13, 15

Step-by-step explanation:

Hard to explain it over the computer, but that is correct.

Hope that this helps!

ANTONII [103]3 years ago
4 0

Answer:

19, 18, 13, 15 (in order)

Step-by-step explanation:

See the attachment >_<

I've marked the order of the numbers in red, as well as the numbers you'll need to add in blue.

Good luck ^^

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(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

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3 years ago
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