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Alik [6]
3 years ago
4

A uniform linear charge density of 4.0nC/m is distributed along the entire x axis. Consider a spherical(radius = 5.0 cm) surface

centered on the origin. Determine theelectric flux through this surface.
1. 79 N · m2/C

2. 45 N · m2/C (what i think itis)

3. 68 N · m2/C

4. 62 N · m2/C

5. 23 N · m2/C (what the reply said itwas)

Physics
2 answers:
Mashutka [201]3 years ago
6 0

Answer:

Ф = 45 N m² / C

Explanation:

For this exercise we use Gauss's law

        Ф = E .dA = qint / ε₀

        A = 4π r²

        Ф = E 4π r² = qint /ε₀  

Since the charge is along the x axis the linear charge density

         λ = q / x

         q = λ x

The charge inside the Gaussian surface is the charge on the line from x = -5 cm to x = 5 cm, so x_total = 10 cm

        Φ = λ x_total / ε₀  

Let's calculate

       Φ = 4.0 10⁻⁹ 0.10 / 8.85 10⁻¹²

       Ф = 45 N m² / C

olganol [36]3 years ago
6 0

Answer:

Electric flux = 23 N · m2/C

Explanation:

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cmcm. She finds that the pen
Art [367]

Hi there!

First, let's find the period of the pendulum. This can be found by solving for the amount of time it takes for the pendulum to make ONE complete swing.

T = \frac{\text{Total time}}{\text{Number of complete swings} }\\\\T = \frac{145}{110} = 1.318 s

Now, let's use the equation for the period of a simple pendulum:
T = 2\pi \sqrt{\frac{L}{g}}

T = Period (1.318 s)
L = length of string (0.55 m)

g = acceleration due to gravity on planet (? m/s²)

Let's solve for 'g' doing some quick rearranging of the equation:
T^2 = 4 \pi^2 (\frac{L}{g})\\\\g = \frac{4\pi^2 L}{T^2}\\\\

Solving for 'g' by plugging in values:
g = \frac{4\pi^2 (0.55)}{(1.318)^2}\\ \\= \boxed{12.496 \frac{m}{s^2}}

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ss7ja [257]

Answer:

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Explanation:

I think not 100% sure

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