Answer:
Minimum distance needed to move one of the mirrors = 125 nm
Explanation:
Constructive interference occurs when the maxima (trough or crest) of two waves that are in phase add together so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes.
Destructive interference occurs when the maxima (trough or crest) of two waves that are out of phase by 180⁰ or half a wavelength combine to produce a smaller amplitude than the individual amplitudes that combine. It can even produce a wave of zero amplitude.
Since the spot of constructive interference has been changed to destructive interference, Path difference = Wavelength/2
Path difference = 500nm/2 = 250 nm
Path difference = 250 * 10⁻⁹ m
Since there are two interferometer's mirrors and only one is moved, the minimum distance will be a half of the path difference.
That is, minimum distance = (path difference)/2
Minimum distance = (250 * 10⁻⁹)/2
Minimum distance = 125 * 10⁻⁹ m
Minimum distance = 125 nm
Explanation:
Heat liberated by a body depends on the mass of the body, the specific heat capacity of that body and the change in temperature experienced by the body.
Heat energy by a body depends on the surface area of the body A as well as the temperature of body T.
According to Stefan's law, rate of heat energy radiated by a body is given by P=σAeT^4
Thus more is the temperature of body, more is the heat radiated. Also mores is the surface area of body, more is the heat radiated.
Answer:
a=-4.2 m/s²
Explanation:
The horse riding so inital velocity is given finally the rider stops so the final velocity is zero.
initial velocity =Vi= 21 m/s
final velocity =Vf= 0 m/s
distance covered = S=52 m
By using 2nd equation of motion we can find the acceleration
2aS=Vf² -Vi²
a=(-441)/104
a=-4.2 m/s²
So the accceleration is 4.2 m/s².
It will not explode since the mass of the cotton balls is so low but rather will most likely break the lock and hinges and come out.
Up until the moment the box starts to slip, the static friction is maximized with magnitude <em>f</em>, so that by Newton's second law,
• the net force acting on the box parallel to the ramp is
∑ <em>F</em> = <em>mg</em> sin(<em>α</em>) - <em>f</em> = 0
where <em>mg</em> sin(<em>α</em>) is the magnitude of the parallel component of the box's weight; and
• the net force acting perpendicular to the ramp is
∑ <em>F</em> = <em>n</em> - <em>mg</em> cos(<em>α</em>) = 0
where <em>n</em> is the magnitude of the normal force and <em>mg</em> cos(<em>α</em>) is the magnitude of the perpendicular component of weight.
From the second equation we have
<em>n</em> = <em>mg</em> cos(<em>α</em>)
and <em>f</em> = <em>µn</em> = <em>µmg</em> cos(<em>α</em>), where <em>µ</em> is the coefficient of static friction. Substituting these into the first equation gives us
<em>mg</em> sin(<em>α</em>) = <em>µmg</em> cos(<em>α</em>) ==> <em>µ</em> = tan(<em>α</em>) ==> <em>α</em> = arctan(0.35) ≈ 19.3°
