Answer:
Explanation:
Given that,
Basketball has a mass of 0.1kg
m = 0.1 kg
The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero
a = 0m/s²
The constant speed is 6m/s
v = 6m/s
So, force to keep it moving with this constant speed can be calculated using Newton second law of motion
F = ma
F = m × 0
F = 0N
So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.
The first step is to represent the vectors shown in the image in Cartesian coordinates.
For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)
To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.
So:
For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)
So:
So:
Finally the sum of B + C is made component by component in the following way:
Finally the magnitude of f is:
| F | = 8.04
Use the kinematics equation:
d = vt + 1/2at^2.
In this problem,
v = 15 m/s.
a = 3 m/s^2,
t = 10 s,
So:
d = 15(10) + 1/2*(3)*(10^2) = 300 meters
Answer:
The force on a bullet that results from summing all of the forces on that bullet is known as the net force on the bullet.
Explanation:
Net force represents the overall force or the total force acting on an object.
Here, the object is bullet and the net force acting on it is the addition of all the forces acting on the bullet.