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zavuch27 [327]
3 years ago
12

The blood flow rate through the aorta is measured to be 104.1 cm^3/s, and an adult is measured to have 4.93 L of blood. How long

does it take for all of your blood to pass through the aorta?
If the adult's aorta has a diamter of 1.85 cm, what is the speed of blood as it flows through the aorta?
Physics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

a)time t = 47.4s

b)speed v = 38.7cm/s

Explanation:

Given:

Total volume of blood = 4.93L × 1000cm^3/L = 4930cm^3

Volumetric rate of flow = 104.1cm^3/s

a) Time taken for all the blood to pass through the aorta is:

Time t = total volume/ volumetric rate

t = 4930/104.1

t = 47.4s

b) Given that the diameter of the aorta is 1.85cm.

V = Av

Where V = Volumetric rate

A = area of aorta

v = speed of blood

v = V/A ...1

Area of a circular aorta = πr^2 = (πd^2)/4

d = 1.85cm

A = (π×1.85^2)/4

A = 2.69cm^2

From equation 1.

v = V/A = 104.1/2.69

v = 38.7 cm/s

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Artist 52 [7]

Answer:

The height of the water column = 1.62405\overline{30} × 10⁻¹ m

Explanation:

The air cavity in the Coke bottle = 0.220 m deep

The fundamental (frequency) it plays when water is added to shorten the column and it is blown across the top, f = 528 Hz

The given speed of sound in air, v = 343 m/s

We note that the air cavity in the coke bottle is equivalent to a tube closed at one end

The fundamental frequency for a tube closed at one end, 'f', is given as follows;

f = v/(4·L) = v/λ

Where;

L = The height of the water column

λ = The wavelength of the wave

∴ 4·L = v/f = (343 m/s)/(528 Hz) = 0.6496\overline{21} m

∴ L = 0.6496\overline{21} m/4 = 0.162405\overline{30} m

The height of the water column = 1.62405\overline{30} × 10⁻¹ m.

4 0
2 years ago
Read 2 more answers
A mass of 5 kg stretches a spring 20 cm. The mass is acted on by an external force of 10 sin t 6 N (newtons) and moves in a medi
nordsb [41]

Answer:

u" + 40u' + 49u = 2 sin(t/6)        

upp + 40up + 49u = 2 sin(t/6)

Explanation:

Step 1: Data given

mass = 5 kg

L = 20 cm = 0.2 m

F = 10 sin(t/6)N

Fd(t) = - 6 N

u(0) = 0.03 m/s

u(0) = 0

u'(0) = 3 cm/s

Step 2:

ω =kL

k = ω/L = m*g /L = (5*9.8)/0.2 = 245 kg/s²

Since Fd(t) = -γu'(t)  we know:

γ =- Fd(t) / u'(t) = 6N/ 0.03 m/s = 200 Ns/m

The initial value problem which describes the motion of the mass is given by

5u" + 200u' + 245u = 10 sin(t/6)   u(0) = 0  ;  u'(0) = 0.03

This is equivalent to:

u" + 40u' + 49u = 2 sin(t/6)        u(0) = 0  ;  u'(0) = 0.03

upp + 40up + 49u = 2 sin(t/6)

With u in m and t in s

5 0
3 years ago
Which statement best describes the circular flow model?
aleksley [76]
Can you please include the statement or the model?
3 0
2 years ago
How much work does the electric field do in moving a proton from a point with a potential of +130 V
In-s [12.5K]

Explanation:

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6 0
3 years ago
F F= {mango, apple, banana, orange)​
Stels [109]

Answer:

<h3>n(F) = 4</h3>

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

F= {mango, apple, banana, orange)​, we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).

Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4

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3 years ago
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