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zavuch27 [327]
4 years ago
12

The blood flow rate through the aorta is measured to be 104.1 cm^3/s, and an adult is measured to have 4.93 L of blood. How long

does it take for all of your blood to pass through the aorta?
If the adult's aorta has a diamter of 1.85 cm, what is the speed of blood as it flows through the aorta?
Physics
1 answer:
STatiana [176]4 years ago
6 0

Answer:

a)time t = 47.4s

b)speed v = 38.7cm/s

Explanation:

Given:

Total volume of blood = 4.93L × 1000cm^3/L = 4930cm^3

Volumetric rate of flow = 104.1cm^3/s

a) Time taken for all the blood to pass through the aorta is:

Time t = total volume/ volumetric rate

t = 4930/104.1

t = 47.4s

b) Given that the diameter of the aorta is 1.85cm.

V = Av

Where V = Volumetric rate

A = area of aorta

v = speed of blood

v = V/A ...1

Area of a circular aorta = πr^2 = (πd^2)/4

d = 1.85cm

A = (π×1.85^2)/4

A = 2.69cm^2

From equation 1.

v = V/A = 104.1/2.69

v = 38.7 cm/s

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Explanation:

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v=v_0-a\,t\\0=v_0-a\,t\\t=v_0/a

We replace this time (t) in the kinematic equation for the particle displacement:

\Delta y=v_0\,(t)-\frac{1}{2} a\,t^2\\\Delta y=v_0\,(\frac{v_0}{a} )-\frac{a}{2} (\frac{v_0}{a} )^2\\\Delta y=\frac{1}{2} \frac{v_0^2}{a}

Replacing the values with the information given, converting the distance d into meters (0.01 m), using \Delta V=100\,V, and the electron's kinetic energy:

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we get:

\Delta\,y= \frac{1}{2} v_0^2\,\frac{m (0.01)}{q\,(100)} =11.2 (1.6\,\,10^{-19})\,\frac{0.01}{(1.6\,\,10^{-19})\,(100)}=\frac{11.2}{10000}  \,meters=0.00112\,\,metersTherefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:

0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]

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