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Sedbober [7]
2 years ago
5

Starting from equilibrium at point 0, what point on the pv diagram will describe the ideal gas after the following process? lock

the piston head in place, and hold the container above a very hot flame.
Physics
2 answers:
dsp732 years ago
5 0

Isobaric Process.

<h2> Further Explanation </h2>

The isobaric process is a thermodynamic process where the pressure is constant: ΔP = 0.

Isobaric stated that if a situation in an ideal gas cylinder has a fixed volume then if the temperature is changed the cylinder pressure will change linearly. In the isobaric process, the system pressure is kept constant.

According to the first law of thermodynamics, where W is the work done on the system, U is the energy in and Q is heated with Δ indicating changes during the process, while d is the differential symbol.

If a gas carries out a thermodynamic process by keeping the pressure constant, the gas is said to carry out an isobaric process. Because gas is under constant pressure, it does business (W = p∆V). The heat here can be expressed as gas heat at a constant pressure Qp. Thus, the work done by gas (W) can be expressed as the difference in energy (heat) that is absorbed by the gas at constant pressure (Qp) with the energy (heat) absorbed by the gas at a constant volume (QV).

In an isobaric process, there is usually a change in internal energy, work is carried out by the system, and heat is transferred so that no amount in the first law of thermodynamics easily reduces to zero.

Learn more

Isobaric Process brainly.com/question/2603204

Details

Grade:  High School

Subject:  Physics

keywords: Isobaric

Anna71 [15]2 years ago
3 0
Since the product of P·Vis constant along an isotherm, an expansion to twice the volume implies a pressure reduction to half the original pressure. I hope my answer has come to your help. God bless and have a nice day ahead!<span>
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Answer:

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5 0
2 years ago
A diverging lens (f1 = -12.0cm) is located 50.0 cm to the left of a converging lens (f2 = 34.0 cm). A 2.0 cm-tall object stands
pishuonlain [190]

Answer:

The final image relative to the converging lens is 34 cm.

Explanation:

Given that,

Focal length of diverging lens = -12.0 cm

Focal length of converging lens = 34.0 cm

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Distance of object = 12 cm

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We need to calculate the image distance of diverging lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

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The image distance is 34 cm right to the converging lens.

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Answer:

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yes

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