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Sedbober [7]
3 years ago
5

Starting from equilibrium at point 0, what point on the pv diagram will describe the ideal gas after the following process? lock

the piston head in place, and hold the container above a very hot flame.
Physics
2 answers:
dsp733 years ago
5 0

Isobaric Process.

<h2> Further Explanation </h2>

The isobaric process is a thermodynamic process where the pressure is constant: ΔP = 0.

Isobaric stated that if a situation in an ideal gas cylinder has a fixed volume then if the temperature is changed the cylinder pressure will change linearly. In the isobaric process, the system pressure is kept constant.

According to the first law of thermodynamics, where W is the work done on the system, U is the energy in and Q is heated with Δ indicating changes during the process, while d is the differential symbol.

If a gas carries out a thermodynamic process by keeping the pressure constant, the gas is said to carry out an isobaric process. Because gas is under constant pressure, it does business (W = p∆V). The heat here can be expressed as gas heat at a constant pressure Qp. Thus, the work done by gas (W) can be expressed as the difference in energy (heat) that is absorbed by the gas at constant pressure (Qp) with the energy (heat) absorbed by the gas at a constant volume (QV).

In an isobaric process, there is usually a change in internal energy, work is carried out by the system, and heat is transferred so that no amount in the first law of thermodynamics easily reduces to zero.

Learn more

Isobaric Process brainly.com/question/2603204

Details

Grade:  High School

Subject:  Physics

keywords: Isobaric

Anna71 [15]3 years ago
3 0
Since the product of P·Vis constant along an isotherm, an expansion to twice the volume implies a pressure reduction to half the original pressure. I hope my answer has come to your help. God bless and have a nice day ahead!<span>
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Can someone please help me because this is a hard problem to solve.
ivolga24 [154]

Answer:

25.0 m / 10 m/s = 2.5 s

50.0 / 9.5 = 5.26 s

25.0 / 11.1 = 2.25 s

T (Wood) = 2.5 + 5.26 + 2.25 = 10.0 s

Mrs Wood runs 10 s vs 10.4 for Mr Overstreet

7 0
2 years ago
A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for
nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block (W), measured in newtons, is:

W = m\cdot g (1)

Where:

m - Mass of the block of ice, measured in kilograms.

g  - Gravitational acceleration, measured in meters per square second.

If we know that m = 14\,kg and g = 9.807\,\frac{m}{s^{2}}, the magnitudes of the weight and normal force of the block of ice are, respectively:

N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

N = W = 137.298\,N

And the pull force is:

F_{pull} = 98\,N

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f} (2)

Where:

v_{o}, v_{f} - Initial and final speeds of the block, measured in meters per second.

\Sigma F - Horizontal net force, measured in newtons.

\Delta t - Impact time, measured in seconds.

Now we clear the final speed in (2):

v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}

If we know that v_{o} = 0\,\frac{m}{s}, m = 14\,kg, \Sigma F = 98\,N and \Delta t = 1.40\,s, then final speed of the ice block is:

v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}

v_{f} = 9.8\,\frac{m}{s}

The final speed of the block of ice is 9.8 meters per second.

6 0
2 years ago
HELP ASAP!! WILL MARK BRAINLIEST
Kitty [74]

Answer:

A

Explanation:

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8 0
3 years ago
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The great lakes in north american hold about what percent of earth's fresh surface water?
fenix001 [56]
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8 0
3 years ago
A bicycle is ridden along a horizontal road with a driving force of 400, n,400n. its speed is constant at 12, m, slash, s,12m/s.
mr_godi [17]

The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

<h3>What is friction force?</h3>

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

Learn more about friction force.

brainly.com/question/1714663

#SPJ1

4 0
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