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3 years ago

12

a man dropped his keys into the sea, and watched them fall to a depth of -8 meters before landing on a rock. how far are the key

s from the surface of the sea?

1 answer:

aleksklad [387]3 years ago

5 0

I’m pretty sure it should just be 8 metres

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4. = 38 -8(n-1), n=1, 2, 3...

stepladder [879]

Answer:

$38-8\left(n-1\right),\:n=123:\quad -938$

$\mathrm{For}\:38-8\left(n-1\right)\:\mathrm{substitute}\:n\space\mathrm{\:with\:}\space123$

$38-8(123-1)= -938$

$-938$

Step-by-step explanation:

5 0

2 years ago

Please help me with this

navik [9.2K]

Answer:

9) C: x=4, y=2rt3

10) A: XY/YZ

11) A: XY/XZ

Step-by-step explanation:

9 - that is a 30, 60, 90 triangle so the ratios will be a, root3a, 2a

10 - tan = opposite / adjacent

11 - cos = adjacent/hypotenuse

7 0

3 years ago

Read 2 more answers

Just took pictures to make it easier.

olganol [36]

Answer:

8. $\displaystyle \frac{9[x + 5]}{x - 14}$

7. $\displaystyle -\frac{2x - 1}{2[3x - 5]}$

6. $\displaystyle \frac{2[x - 4]}{5[x + 3]}$

5. $\displaystyle \frac{2x + 7}{x + 3}$

4. $\displaystyle 3x^{-1}$

Step-by-step explanation:

All work is shown above from 8 − 4.

I am joyous to assist you anytime.

3 0

3 years ago

Which equation represents the graph?

DerKrebs [107]

Answer:

?

Step-by-step explanation:

What are the equations

6 0

3 years ago

Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.

Step2247 [10]

Answer:

Remember, the expansion of $(x+y)^n$ is $(x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k$ , where $\binom{n}{k}=\frac{n!}{(n-k)!k!}$ .

Then,

$(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k$

Then, the coefficient of the term $p^{6-k}q^k$ is $\binom{6}{k}5^{6-k}2^k$

a) since 6-k=2, then k=4. So the coefficient of $p^2q^4$ is

$\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000$

b) since 6-k=5, then k=1. So, the coefficient of $p^5q$ is

$\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500$

c) since 6-k=3, then k=3. So, the coefficient of $p^3q^3$ is

$\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000$

6 0

3 years ago