Answer:
False
Explanation:
Igor did nothing wrong. He performed a reverse engineering process which is totally legal. A reverse engineering process happens when a manufactured object is deconstructed in order to find out how it was designed or manufactured.
This process is very similar to scientific research, only that it is carried out on man made objects.
Answer:
Explanation:
The statement in the question is not complete and should be the following with each of the answers provided being part of the statement like so,
Management of a close corporation often resembles that of a Partnership , but a corporation must meet the statutory requirements to remain a corporation. Often, shareholders in a close corporation restrict the transferability of shares. If a majority shareholder misappropriates company funds, the normal remedy for the other shareholders is to have their shares appraised to determine value and then receive that value.
Answer:
The answer is: $3,289
Explanation:
<u>Date</u> <u>Units </u> <u>Unit price</u> <u>Inventory</u> <u>Average cost</u>
Purchases
Nov. 1 103 units $20 per unit $2,060 $20 per unit
Nov. 5 103 units $22 per unit $4,326 $21 per unit
Nov. 8 53 units $23 per unit $5,545 $21.41 per unit
<u>Nov. 19 30 units $25 per unit $6,295 $21.78 per unit</u>
TOTAL 289 units $21.78 per unit $6,295 $21.78 per unit
Sales
Nov. 16 -138 units $21.78 per unit $3,006 $21.78 per unit
Ending inventory
Nov. 30 151 units $21.78 per unit $3,289 $21.78 per unit
First, you have to calculate the amount of tuition when the student reaches age 18. Do this by multiplying $11,000 by 1.07 each year from age 12 until it reaches age 18. Thus, 7 times.
At age 18: 16,508
At age 19: 17,664
At age 20: 18,900
At age 21: 20,223
Then, we use this formula:
A = F { i/{[(1+i)^n] - 1}}
where A is the monthly deposit each year, F is the half amount of the tuition each year illustrated in the first part of this solution, n is the number of years lapsed.
At age 18:
A = (16508/2) { 0.04/{[(1+0.04)^6] - 1}} = $1,244.389 deposit for the 1st year
Ate age 19
A = (17664/2) { 0.04/{[(1+0.04)^7] = $1,118 deposit for the 2nd year
At age 20:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $1,025 deposit for the 3rd year
At age 21:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $955 deposit for the 4th year