Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of the vertices are,
Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)
Following the rule of translation by 3 units to the right and 2 units down 
(x, y) → (x+3, y-2)
Q(1, 3) → Q''(4, 1)
R(3, -3) → R"(6, -5)
S(0, -2) → S"(3, -4)
T(-2, 1) → T"(1, -1)
Following rule 
(rotation of a point by 180° about the origin) will give the image points,
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)
The differential equation that has the given slope is: dy/dx = -xy.
<h3>How to find the differential equation that models the situation?</h3>
We have to look at the slope, given in the graph of the solution of the differential equation, and represented by dy/dx. From the graph, we have that:
- In quadrants I and III, in which x and y have the same signal, the differential equation is decreasing, hence the slope is negative.
- In quadrants II and IV, in which x and y have different signals the differential equation is increasing, hence the slope is positive.
The differential equation that is negative when x and y have the same signals and positive when they do not have is given by the following option:
dy/dx = -xy.
More can be learned about differential equations at brainly.com/question/14423176
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-2.5 and 4
You can get this by factoring to the equation (2x + 5)(x - 4)
