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Juli2301 [7.4K]
2 years ago
12

Urgent help please . it’s important and i’m stuck

Mathematics
1 answer:
Nina [5.8K]2 years ago
5 0

Answer: The image wont lode, sorry.

Step-by-step explanation:

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shutvik [7]

Answer:

35

Step-by-step explanation:

7 0
2 years ago
A bottle holds z ounces of water. A second bottle holds 16 ounces, which is 8/5
Katen [24]

Answer:

The first bottle holds 25 3/5 ounces of water.

Step-by-step explanation:

16 x 8/5

= 16/1 x 8/5

= 128/5

= 25 3/5

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2 years ago
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Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
Now, you do the math: Tell us if you can afford the apartment using the details below. . Your gross paycheck is $2100 per month.
Serhud [2]

Answer:

yes

Step-by-step explanation:

5 0
2 years ago
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Find the value of x in the picture please
Marianna [84]

Answer:

Option B. The value of x is 20

Step-by-step explanation:

we know that

<u>The intersecting chords theorem</u>  states that the products of the lengths of the line segments on each chord are equal.

so

In this problem

(x)(x-11)=(x-8)(x-5)\\x^{2}-11x=x^{2}-5x-8x+40\\-11x=-13x+40\\2x=40\\x=20

3 0
3 years ago
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