The series of steps in which large fish eats a small fish that has eaten algae is a:

water molecules evaporate from a lake near the equator and rise into the atmosphere, as shown in the diagram below. as the molec

valentinak56 [21]

<u>Condensation</u> is the next step in the water cycle that is most likely to happen next as water molecules evaporate from a lake near the equator and rise into the atmosphere, as shown in the diagram below. and as the molecules travel away from the equator.

Explanation:

As the warmer air mass rises into the upper atmosphere, at the equator, it begins to cool because temperatures drop with altitude. The relative humidity of the air mass increases until it reachesdew point. The water vapor begins to condense into water droplets.

This air mass begins moving towards the poles (away from the equator) bringing with it clouds (condensed water vapor) that precipitate later on. This air mass begins to sinks because it has become denser with a decrease in temperature. As it sinks it replaces the air mass moving to the equator. The air rushing to the equator is replacing the rising warm air mass at the equator. This cycle continues.

Learn More:

For more on the water cycle check out;

brainly.com/question/11437446?section=related_q

brainly.com/question/978359

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4 0

3 years ago

The answer is 51.0 ml but can someone explain why please

professor190 [17]

Answer:

$\boxed{\sf A. \ 51 \ mL}$

Explanation:

Amount of water displaced by the sphere will be equal to the volume of complete sphere.

As the sphere completely sinks to the bottom of the cup.

We have been given;

Diameter of sphere (d) = 4.6 cm

So,

$\sf Radius \: of \: sphere \: (r) = \frac{Diameter \: of \: sphere \: (d)}{2} \\ \sf = \frac{4.6}{2} \\ \sf = 2.3 \: cm$

Volume of sphere (V):

$\boxed{ \bold{V = \frac{4}{3} \pi {r}^{3} }}$

By substituting value of r we get:

$\sf \implies V = \frac{4}{3} \times \pi \times {(2.3)}^{3} \\ \\ \sf \implies V = \frac{4}{3} \times 3.14 \times 12.167 \\ \\ \sf \implies V = \frac{152.81752}{3} \\ \\ \sf \implies V = 50.94 \: {cm}^{3} \\ \\ \sf \implies V \approx 51 \: {cm}^{ 3}$