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ankoles [38]
3 years ago
12

If the center of the circle were moved from the origin to the point (h, k) and point P at (x, y) remains on the edge of the circ

le, which could represent the equation of the new circle?
Mathematics
2 answers:
Fantom [35]3 years ago
7 0

Answer:

(x-h)^2 + (y-k)^2 = r^2

Step-by-step explanation:

edgenuity 2020

hope this helps!

Art [367]3 years ago
3 0

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Question 2 In the fall, a community service club sold 10 shirts and 20 hats for a total of $490. In the spring, the club sold 20
Stells [14]
To answer the question above, we let s be the cost of a shirt and h be the cost of each hat such that the equations that would best represent the given are:
                                        10s + 20h = 490
                                         20s + 30h = 860
The system of equations is the answer to the first question and the values of s and h are $25 and $12, respectively. 
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3 years ago
What is the value of 4b ÷ 3, if b =3
Mice21 [21]
The value is 4 because 4b is also 4 times three which is twelve then you divide 12  by three and get 4

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2 years ago
What is the x-value in the solution to this equation of linear equations? 2x-y=11 x+3y=-5
saw5 [17]

The solution to these linear equations is (4,-3)

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The equation below can be used to solve which of the following word problems? 2x + 4y = 18
densk [106]
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7 0
3 years ago
. Leslie is blowing up one of her favorite photographs to hang on her wall. If the photo's original length and height were 8 inc
Katena32 [7]

Answer:

L_2 = 2\frac{2}{15}\ ft

Step-by-step explanation:

Given

Original

Length(L_1) = 8\ in

Height (H_1) = 15\ in

New

Height (H_2) = 4\ ft

Required

Determine the new length (L2)

Since the original photographs was blown up; the original and the new photographs would have the same ratio

i.e.

Ratio = L_1 : H_1

and

Ratio = L_2 : H_2

Equate both ratios

L_1 : H_1 = L_2 : H_2

Rewrite as fraction

\frac{L_1}{H_1} = \frac{L_2}{H_2}

Substitute values for L1, H1 and H2

\frac{8}{15} = \frac{L_2}{4}

Multiply both sides by 4

4 * \frac{8}{15} = \frac{L_2}{4} * 4

4 * \frac{8}{15} = L_2

\frac{4 * 8}{15} = L_2

\frac{32}{15} = L_2

2\frac{2}{15} = L_2

L_2 = 2\frac{2}{15}\ ft

The new length must be 2\frac{2}{15}\ ft

7 0
3 years ago
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