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yawa3891 [41]
2 years ago
8

If the simple interest on ​$3,000 for 4 years is ​$960​, then what is the interest​ rate?

Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

8%

Step-by-step explanation:

R = 100 x I/P x t

Given

Interest I = $960

Principal P = $3000

Time t = 4 yrs

Rate R = ?

R = 100 x 960 /3000 x 4

Multiply through

R = 96000/12000

R = 8

R = 8%

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Hi there,

The answer to your question is:

B. 120

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Dus4nR
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3 years ago
If your salary is $42,500 and your federal income taxes are 10% of your salary, how much money will you owe this year in federal
DiKsa [7]
42,500 X 0.10 = $4250.
You owe $4250!!
3 0
2 years ago
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The fitted regression is Sales = 832 − 28.2 Price. (a-1) If Price = 1, what is the prediction for Sales? (Round your answer to 1
almond37 [142]

Answer:

Part (a-1): The prediction for Sales is 803.8.

Part (a-2): The correct option is: An increase in price decreases sales.

Part (B): The prediction for sales is 211.66

Part (C): The intercept is meaningful as sales will be maximized when price is zero.

Step-by-step explanation:

Consider the provided regression:

Sales = 832 − 28.2 Price

(a-1) If Price = 1, what is the prediction for Sales?

Substitute Price = 1 in above regression.

Sales = 832 − 28.2 (1) = 803.8

Hence, the prediction for Sales is 803.8.

Sales (a-2) Choose the correct statement.

Here we can observe that as we increase the price, sales decrease.

Thus, the correct option is: An increase in price decreases sales.

(b) If Price = 22, what is the prediction for Sales?

Substitute Price = 22 in above regression.

Sales = 832 − 28.2 (22)

Sales = 832 − 620.4

Sales = 211.66

Hence, the prediction for sales is 211.66

Sales (c) Choose the right option.

As we increase the price, sales decrease that means the sales will be maximum if the price is 0.

The intercept is meaningful as sales will be maximized when price is zero.

3 0
3 years ago
Suppose A is an invertible n×n matrix and v is an eigenvector of A with associated eigenvalue 4. Convince yourself that v is an
mote1985 [20]

The eigenvector of matrix A4 is 4096.

The eigenvalue of the matrix A-1 is 1/8.

(A+4I) has an eigenvalue of 12.

40 is the eigenvalue of 5Av.

The collection of scalar values known as the eigenvalues of a matrix are connected to the set of linear equations that are most likely contained within the matrix equations.

The eigenvectors are also known as the characteristic roots.

If the matrix A's eigen vector v is linked to an eigen value.

Av then equals lamda v.

The fact that v is an eigen vector of A with the value eight is assumed.

hence, Av = 8v.

We must determine the eigenvalue of A4.

A4*v equals A3(8v) = 84*v equals 4096v.

As a result, the eigenvalue of A4 is 4096.

Suppose A has an eigenvalue of 8. The eigenvalue of A-1 is thus 1/8.

It is calculated that the eigenvalue of (A+4I) is (A +4In)v = Av + 4v = 8v + 4v =12v.

(A+4I) has an eigenvalue of 12.

The value of 5Av's eigenvalue is 5Av = 5*8v = 40v.

40 is the eigenvalue of 5Av.

Learn more about the eigen vectors here:

brainly.com/question/15423383

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11 months ago
Click on the photo! Needing help ASAP please!♥️
Lana71 [14]
A
This is like a base form of a prime polynomial
X^2+x+1
5 0
3 years ago
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