All categories

3 years ago

Helpppppppppppppmeeee

Mathematics

1 answer:

tino4ka555 [31]3 years ago

8 0

B. 4.1 would be the right answer.

You might be interested in

(6y-7)(3y+1) = 18^y+27y+7y?

garik1379 [7]

Answer:

18y²-15y-7

Step-by-step explanation:

6y×3y-7×3y+6y×1-7×1

=18y²-21y+6y-7

=18y²-15y-7

3 0

3 years ago

-3,1,5,13 find the sequence

geniusboy [140]

Answer:

add 4 twice then add 8 twice

hope this helps

have a good day :)

Step-by-step explanation:

3 0

3 years ago

How are inequality and equation similar and different

Vadim26 [7]

They are similar because there are 2 sides to them. they are different because an equation states that both sides are equal, but in an inequality, one side is either greater than, less than, greater than or equal to, or less than or equal to.

3 0

4 years ago

What is the slope of the line tangent to the graph of y = (9x^2)/(x+2) at x = 1 ?

lidiya [134]

Using derivatives, it is found that the slope of the line tangent to the graph of y at x = 1 is of 5.

The equation is:

$y(x) = \frac{9x^2}{x + 2}$

The slope of the line tangent to the graph of y at x = 1 is $y^{\prime}(1)$ .

Applying the quotient rule, we have that:

$y^{\prime}(x) = \frac{[9x^2]^{\prime}(x + 2) - [x + 2]^{\prime}(9x^2)}{(x + 2)^2}$

$y^{\prime}(x) = \frac{18x(x + 2) - 9x^2}{(x + 2)^2}$

$y^{\prime}(x) = \frac{9x^2 + 36x}{(x + 2)^2}$

Then, when x = 1:

$y^{\prime}(1) = \frac{9(1)^2 + 36(1)}{(1 + 2)^2} = \frac{45}{9} = 5$

The slope of the line tangent to the graph of y at x = 1 is of 5.

You can learn more about the use of derivatives to find the slope of a tangent line at brainly.com/question/10580177

6 0

2 years ago

a rectangle is 4 times as long as its width.its perimeter is 50cm. what are the dimensions of the rectangle?

kenny6666 [7]

5 and 20 because if the perimeter is 50 the width is 5 and 5 x 4 is 20

8 0

4 years ago