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DedPeter [7]
3 years ago
6

What is the area? 6 mm 5 mm 3 mm 13 mm 8 mm 9 mm

Mathematics
1 answer:
Mkey [24]3 years ago
5 0

Answer:

none of above .

Step-by-step explanation:

because the unit of area is always in square forms.

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const2013 [10]

Answer:just do the math mate

Step-by-step explanation:

6 0
3 years ago
Whats the word phrase of 49+m?
Arturiano [62]
The sum of 49 and m.
3 0
3 years ago
Read 2 more answers
Picture provided help!
weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

2u - 6v

(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0
3 years ago
Guys please help me with this question
Bond [772]

Answer:

y=4/3x+15 1/3 (or) y=4/3x+46/3

Step-by-step explanation:

If it’s parallel, it has to have the same slope (4/3).  

Plug 7 in for x, and then find out what you have to do to make y equal -6.

y=4/3x+15 1/3 (or) y=4/3x+46/3

3 0
3 years ago
Please Help. Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy
velikii [3]

Answer:

1. The equation is given as

324 = 220 +135 + C

2. We have 166 As the correct answer but is not in the option

Step-by-step explanation:

We are been given the following values

No. of trophies = 3

Total Legos required for all trophies = 324

No. of Legos for largest trophy(A) = 220

No. of Legos for smallest trophy(B) = 135

No. of Legos required for final trophy(C) which is unknown

Total legos will addition of everything

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]

Substituting the values

324 = 220 +135 + C

Making C subject of formula

324 = 355 + C

324 - 355 = C

-31 = C

135 + 31 = 166

We have 166 As the answer

8 0
3 years ago
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