Answer:
As a cell grows in size, the surface area gets bigger, but the volume gets bigger faster. Thinking about this as a ratio (division), the volume is the denominator and the surface area is the numerator. If the volume is getting very big, then the ratio itself will be getting very small.
Answer: The simplest way is to determine if a strain is mutant is observing morphology, growth rate, double time, etc but it is accurate if you can prove if the strain is deficient in one aminoacid or can't metabolize lactose, etc.
Explanation: A wildtype strain functions normally, for example, can metabolize as a carbon source, glucose, lactose and other sugars, can synthesize all the aminoacids requered for protein synthesis, etc. If a strain suffers a mutation and it is inheritable, the strain become a mutant. Since several mutations can be silent ones, only those that interfere with a process, can be assesed easyly.
For example, if you have several strains and put them in a lactose medium, but some of them cannot growth means that are lactose mutants. Those strains could carry a mutation in genes that encode lactose degrading enzymes or in regulatory genes of the lac operon, etc.
A symbiosis is an evolved interaction or close living relationship between organisms from different species, usually with benefits to one or both of the individuals involved.
8H2. The actual equation doesn't make sense for 8H2. This is because in compounds it always says the number of atoms after the element symbol, but in this case, there is an 8 before it. This means that it isn't a compound.
Answer:
Man's genotype: XᴮY
Woman's genotype: XᴮXᵇ
Daughter's genotype: XᵇXᵇ
The daughter is not the man's child.
Explanation:
Color blindness is a sex-linked trait caused by a recessive allele located in the X chromosome (Xᴮ=normal vision; Xᵇ-color blind).
Women have two X chromosomes, while men have an X and a Y chromosomes. For that reason, women need to have two recessive alleles to be color blind, while men only need one Xᵇ to be colorblind.
Since the man has normal color vision, his genotype would be XᴮY.
If the daughter is her father's, she would have inherited his dominant Xᴮ allele, so she would have normal vision. However, she is colorblind, so her genotype is XᵇXᵇ. She is not the man's daughter.
The mother also has normal color vision, but her daughter inherited a recessive allele from her, so her genotype is heterozygous XᴮXᵇ.
