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lozanna [386]
3 years ago
12

A rectangular field is 27 meters long and 18 meters wide. If fencing costs $12 per yard, how much will it cost to enclose the fi

eld?
Mathematics
2 answers:
Zina [86]3 years ago
7 0

Answer:

1080 dollars

Step-by-step explanation:

Well you said yards and meters but imma ingore that.

So the perimeter is 27+27+18+18 = 90

90*12= 1080

valentinak56 [21]3 years ago
6 0

Answer:

$1080

Step-by-step explanation:

27 \times 2 + 18 \times 2 = 90 \\ 90 \times 12 = 1080

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WILL MARK BRAINLIEST AND WORTH 30 POINTS
BabaBlast [244]

Answer:

The growth factor of <em>f(x)</em> is <em>less</em><em> </em><em>than</em><em> </em>the growth factor of <em>g(x)</em>.

Explanation:

\displaystyle g(x) = 3(4)^x \\ \\ f(x) = 4(3)^x

<em>x</em><em> </em> | <em>f(x)</em>

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0 | 4

1 | 12

2 | 36

You can tell because the <em>g</em><em>(</em><em>x</em><em>)</em><em> </em>function is multiplying by 4, while the <em>f</em><em>(</em><em>x</em><em>)</em><em> </em>function is multiplying by 3.

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4 years ago
How many decimals are between 0,5 and 0,6 ?
dusya [7]

Between 0.5 and 0.6 can be an infinity.

<em><u>ex:</u></em><u /><u><em /></u><em />

0.51

0.52

0.517

0.5169889549.......

0.5999999999..........

etc.

5 0
3 years ago
Read 2 more answers
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
4 years ago
An ostrich that is 100 inches tall is 15 inches taller than 5 times the height of a kiwi. What is the height of a kiwi in inches
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just follow the steps:

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4 years ago
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