state the formula for potassium hydroxide and explain, in terms of charges, how you formed the formula

1 answer:

3 0

Potassium oxide is an ionic compound. The potassium has a charge of K+ and oxygen has a charge of O2−. We need 2 potassium ions to balance one oxide ion making the formula K2O.

Potassium hydroxide is an ionic compound. The potassium has a charge of K+ and hydroxide has a charge of OH−. We need 1 potassium ion to balance one hydroxide ion making the formula KOH.

K2O+ H2O→KOH

To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.

K2O+H2O→2KOH

I hope this was helpful.

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The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = $90$ ( moles of chloroform )

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$K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }$

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Now, we substitute our given values into the equation

$10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform} \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10$