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3 years ago

Fern spores usually form during: winter summer fall spring

Chemistry

2 answers:

nikdorinn [45]3 years ago

6 0

Answer:

they generally form during the summer.

Explanation:

hope I helped. :)

Eddi Din [679]3 years ago

3 0

Answer:

Summer.

Explanation:

Plants we see as ferns or horsetails are the sporophyte generation. The sporophyte generally releases spores in the summer. Spores must land on a suitable surface, such as a moist protected area to germinate and grow into gametophytes.

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What experimental evidence can you provide that the product isolated is 1-bromobutane?

Blizzard [7]

The experimental evidence that you could provide that the product isolated is 1-bromobutane would be the changes that happens that are observable by the naked eye. Hope this helps. Have a nice day. Feel free to ask more questions.

5 0

4 years ago

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Which chemical equation correctly represents the reaction that takes place when nitrogen gas and hydrogen gas are formed as ammo

Leviafan [203]

Answer:

d. 2NH3(g)-N2(g)+3H2(g)

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3 years ago

6. A sample of a gas has a mass of 0.527 g. Its volume is 0.35 L at a temperature of 88 degree Celsius and a pressure of 945 mm

Stels [109]

Answer: The molar mass of the gas is 35.87 g/mol.

Explanation:

To calculate the mass of gas, we use the equation given by ideal gas:

PV = nRT

or,

$PV=\frac{m}{M}RT$

where,

P = Pressure of gas = 945 mmHg

V = Volume of the gas = 0.35 L

m = Mass of gas = 0.527 g

M = Molar mass of gas = ? g/mo

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

T = Temperature of gas = $88^oC=[88+273]=361K$

Putting values in above equation, we get:

$945mmHg\times 0.35L=\frac{0.527g}{M}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 361K\\\\M=35.87g/mol$

Hence, the molar mass of the gas is 35.87 g/mol.

5 0

4 years ago

A(n) _______________ compound is a group of atoms held together by chemical bonds.

Arlecino [84]

Is molecule an answer? It wouldn't let me see all the answers. if it is, molecule is the correct answer. they are held together by a covalent bond, I believe.

3 0

3 years ago

A 0.500 m solution of a weak base has a ph of 9.75. what is the base hydrolysis constant, kb, for the weak base?

Vladimir [108]

When we have PH = 9.75
So we can get POH = 14 - 9.75 = 4.25
and when POH = - ㏒[OH-]
by substitution:
4.25 = -㏒[OH-]
∴[OH] = 5.6x10^-5
from this reaction equation:
BOH ↔ B+ + OH-
∴[OH-] = [B+]= 5.6x10^-5 M
and Equ [BOH] = 0.5 m - X
= 0.5 - (5.6x10^-5)
= 0.4999
∴ Kb = [OH-][B+]/[BOH]
= (5.6x10^-5)^2 / 0.4999
= 6.27x10^-9

8 0

3 years ago