The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-
2x^2 - 4x - x + 2 = 0
now factor by grouping
2x(x - 2) - 1(x - 2) = 0
(x - 2) is common so
(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.
The last example is solved in the same way.
#8: $900. (I found this answer by multiplying 3000 and 0.3 by the way)
#9: 160 miles. I found this answer by multiplying 80 by two, since two halves/50% make a whole or 100%.
Hey!
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Answer: Yes 3/6 is rational!
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Why? Well, because 3 and 6 are integers that don't repeat. 3/6 simplifies to 1/2 or 0.5 which doesn't repeat so it's rational.
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Hope This Helped! Good Luck!
We have,
t = 6.21 s
s = 111 m
u = 0 m/s
To determine: "a" of the particle.
We know,
s = ut + ½ at²
⇒ s = ½ at²
⇒ a = 2s/t²
⇒ a = [2(111 m)]/(6.21 s)²
⇒ a = (222 m)/(38.5641 s²)
⇒ a ≈ 5.75 m/s²
Answer:
Step-by-step explanation:
a) y-intercept is when x=0
f(0)
=1/(0-3)
=-1/3
g(0)=0 from the graph
b) vertical asymptotes are vertical lines that f(x) and g(x) get close but do not exist there
