What is the annual interest rate for an account that compounds monthly at a rate of 2.5%
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Hey!
Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get
on its own.
<em>Original Equation : </em>
< 
<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
< 
( )
And we simplify the equation to get our answer.
<em>Old Equation :</em>
< 
( )
<em>New Equation {Changed by Simplification} :</em>
y < -6
<em>So, the equation < -3 simplified is</em> y < -6.
Hope this helps!
- Lindsey Frazier ♥
Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get
<em>Original Equation : </em>
<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
And we simplify the equation to get our answer.
<em>Old Equation :</em>
<em>New Equation {Changed by Simplification} :</em>
y < -6
<em>So, the equation
Hope this helps!
- Lindsey Frazier ♥
Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:
Z = 1
Z = 1 has a p-value of 0.84.
X = 72:
Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
More can be learned about the normal distribution at brainly.com/question/24663213
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