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alexira [117]
3 years ago
7

Evaluate the following expression when x = -5 and y = 25.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

5

Step-by-step explanation:

5÷5x and 25÷5

1 × 5

your answer is 5

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For what values of x is x2-36=5x true? -9 and -4 -4 and 9 4 and -9 9 and 4.
Norma-Jean [14]

Answer: -4 and 9

Step-by-step explanation:

5 0
3 years ago
X+4
mr Goodwill [35]

Answer:

Step-by-step explanation:

(x + 4)/(x+4)(x-3)

= 1/(x-3)

solution is option 4

3 0
2 years ago
What are all the composite numbers from 1 to 100
Anastaziya [24]

Answer:

4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81,82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.

Step-by-step explanation:

its pretty simple...

6 0
3 years ago
I need help with this problem
Soloha48 [4]

Answer:

3.\ \dfrac{3x}{11x}, \dfrac{6}{22},  \dfrac{9}{33},\dfrac{12}{44}

4. -18\\5.\ 400

Step-by-step explanation:

<u>Solution 3:</u>

Equivalent fractions to are to \frac{3}{11} be found out.

<u>Method: </u> By Multiplying both the denominator and numerator with the same number, we can easily find equivalent fractions.

1. Multiply with 2:

\dfrac{3 \times 2}{11 \times 2}\\\Rightarrow \dfrac{6}{22}

2. Multiply with 3:

\dfrac{3 \times 3}{11 \times 3}\\\Rightarrow \dfrac{9}{33}

3. Multiply with 4:

\dfrac{3 \times 4}{11 \times 4}\\\Rightarrow \dfrac{12}{44}

If we try to write in variable form, it can be written as:

\dfrac{3x}{11x}

where x is any number.

---------------

<u>Solution 4:</u>

(2x-10) when x=-4

2 \times (-4) -10\\\Rightarrow -8 -10\\\Rightarrow -18

------------

<u>Solution 5:</u>

(10a)^2, a=-2\\\Rightarrow \{10 \times (-2)\}^2\\\Rightarrow (-20)^2\\\Rightarrow 400

4 0
3 years ago
Select all correct conversions.
dem82 [27]
All of them are correct except the first and second one. ( 53 km = 53,000m) (23 cm = 230mm)
6 0
3 years ago
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