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crimeas [40]
3 years ago
6

What is the concentration in molarity of a solution made using 50.0 grams of C6H12O6 in 300.0 mL of water?

Chemistry
2 answers:
oee [108]3 years ago
7 0

Answer: concentration in Molarity it's actually Molarity

Molarity=concentration/molar mass

Concentration=50g/0.3dm³=166.67g/dm³

Molar mass=180g/mol

Molarity=0.926mol/dm³

Sladkaya [172]3 years ago
7 0

Answer:

Answer is =0. 925 mol L−1

Explanation:

C₆H₁₂O₆ is formula of Glucose  

For Molarity, we must know the following things  

• the number of moles of solute present in solution

• the total volume of the solution

we know the mass of one mole of Glucose = 180.156 g/mol

Number of moles = Given Mass of substance / Mass of one mole

No of moles = 50g / 180.156 g/mol

                   = 0.277 moles  

Now we know that  molarity is expressed per liter of solution. Since you dissolve 0.277 moles of potassium chloride in 300. mL of solution, you can say that 1.0 L will contain

For 300 ml of solution, no of moles are = 0.277 moles

For 1 ml of solution, no of moles are = 0.277/300 moles

For 1(1000) ml of solution, no of moles are=  0. 277/300 x 1000

                                                                 = 0.925 moles/ L

Answer is =0. 925 mol L−1

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2 years ago
Sn + 2 H2SO4 → SnSO4 + SO2 + 2 H2O If 219.65 grams of SnSO4 are produced, how many moles of H2SO4 were reacted?​
anygoal [31]

Answer:

2.05moles

Explanation:

The balanced chemical equation in this question is as follows;

Sn + 2H2SO4 → SnSO4 + SO2 + 2H2O

Based on the above equation, 2 moles of H2SO4 reacted to produce 1 mole of SnSO4

However, the mass of SnSO4 produced is 219.65 grams. Using mole = mass/molar mass, we can find the number of moles of SnSO4 produced.

Molar mass of SnSO4 where Sn = 118.7, S = 32, O = 16

= 118.7 + 32 + 16(4)

= 150.7 + 64

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mole = 219.65/214.7

mole = 1.023mol

Therefore, if 2 moles of H2SO4 reacted to produce 1 mole of SnSO4

1.023 mol of SnSO4 produced will cause: 1.023 × 2/1

= 2.046moles of H2SO4 to react.

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3 years ago
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soldi70 [24.7K]

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C. Its oxidation number increases.

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g

but A i supposed?

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