The equation for the dissolution of the copper II phosphate is first written as shown and the ICE table is set up as also shown. S is obtained as shown and this is now used to obtain 2s and subsequently the solubility product of the calcium phosphate as shown in detail in the image attached to this solution. The step-by-step solution shows how to obtain Ksp when concentration at equilibrium is given.

3 0

4 years ago

What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.

DIA [1.3K]

Answer:

Q = 31798.4J = 31.79kJ

Explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ

6 0

3 years ago

A 650.0 mL solution contains 125 grams of glucose (C6H12O6). If the molar mass of C6H12O6 is 180.16 g/mol, what is the molarity

Aleks [24]

Molarity of a solution is the molar concentration, which is the number of moles of solute in 1 L of solution.

the mass of glucose is - 125 g

number of moles of glucose - 125 g / 180.16 g/mol = 0.694 mol

the number of moles of glucose in 650.0 x 10⁻³ L - 0.694 mol

number of moles of glucose in 1 L - 0.694 mol / 650.0 x 10⁻³ L = 1.068 mol/L

molarity of glucose solution is 1.068 M

4 0

3 years ago

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