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Anna11 [10]
3 years ago
6

How does calcium obey the octet rule when reacting to form compounds?

Chemistry
2 answers:
wolverine [178]3 years ago
8 0
The answer is C. because it gives up two electrons.
Leya [2.2K]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

Atomic number of calcium is 20 and its electronic distribution is 2, 8, 8, 2.

Therefore, a calcium atom contains two valence electrons and in order to attain stability it needs to lose two electrons.

Hence, it acquires a charge of +2 as Ca^{2+} by loss of two electrons.

As, according to the octet rule there must be eight electrons in the valence shell.

Thus, we can conclude that calcium obey the octet rule when reacting to form compounds as gives up electrons.

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3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
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Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

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3 years ago
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