![\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}](https://tex.z-dn.net/?f=%5Ctt%20-%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2O%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B1%7D%5Cdfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
<h3>Further explanation</h3>
Reaction
2N2O(g) — 2N2(g) + O2(g)
Required
relative rate
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
so the relative rates for the reaction above are :
![\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}](https://tex.z-dn.net/?f=%5Ctt%20-%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2O%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B1%7D%5Cdfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
Answer:
O=O bond
Explanation:-
Note it down that the bond having highest Hydrogen enthalpy has strongest bond.
Now
- O=O(495KJ/mol)
- O-O(146KJ/mol)
- O-H(467KJ/mol)
- H-H(432KJ/mol)
Hence

Answer: The oxygen atom in a water molecule carries a negative electrical charge.
Explanation:
A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.
Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom (attached with an electronegative atom e.g. O, N and F) and an electronegative atom (O,N and F).
In ,
, O is a highly electronegative atom attached to a H atom through a covalent bond. Therefore O atom gets partial negative charge and H atoms get partial positive charge.
Answer:
hydrogen oxygen or nitrogen