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Whitepunk [10]
3 years ago
13

HURRY What is the volume of a cube with an edge length of 0.843

Chemistry
2 answers:
andrezito [222]3 years ago
8 0

Answer: 0.6

Explanation:Yes

mezya [45]3 years ago
4 0

Answer:

5.004

Explanation:

............

............

.my Rude g ubddvbrbrbr

sorry in a hurry

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Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
tatuchka [14]

Answer:

See explanation and images attached

Explanation:

a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.

b)  In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.

5 0
3 years ago
If gas is $4.00/gal, how much does it cost to travel from Portland, Maine, to Orlando, Florida (a distance of 1,500 mi)? Give yo
AlexFokin [52]

it cost $200 , the answer is not $6000

6 0
4 years ago
Read 2 more answers
A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.
Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L

Therefore, the new volume of the air is, 6.83 L

6 0
4 years ago
In the combustion chamber of an engine, the initial volume is 450 cm3 at a pressure of 1.0 atmosphere. If the piston displaces 4
Alona [7]

Assuming that the contents of the chamber ar ideal gases. We can use the relation PV=nRT.  At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

P2 = (1)(450)/ 48

P2 = 9.375 atm

3 0
3 years ago
The nuclear mass of 56fe is 55.9207 amu. calculate the binding energy per nucleon for 56fe.
Aneli [31]

Fe (iron) has 26 protons,30 neutrons and 26 electrons. In order to calculate the binding energy, first you need to find the total mass of all particles in the nucleus:

<span>
<span>26 x mass of proton + 30 x mass of neutron ( all in a.m.u.) = say "m" </span></span>

<span>
Mass defect is m- 55.9207 amu, then convert it into grams and put in equation E = mc2 to get binding energy of Fe.</span>

<span> Divide it by number of nucleons to get binding energy per nucleon</span>.

8 0
3 years ago
Read 2 more answers
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