Answer:
0.73L
Explanation:
The following data were obtained from the question :
V1 = 0.65 L
P1 = 3.4 atm
T1 = 19°C = 19 + 273 = 292K
V2 =?
P2 = 3.2 atm
T2 = 36°C = 36 + 273 = 309K
The bubble's volume near the top can be obtain as follows:
P1V1 /T1 = P2V2 /T2
3.4 x 0.65/292 = 3.2 x V2 /309
Cross multiply to express in linear form as shown below:
292 x 3.2 x V2 = 3.4 x 0.65 x 309
Divide both side by 292 x 3.2
V2 = (3.4 x 0.65 x 309) /(292 x 3.2)
V2 = 0.73L
Therefore, the bubble's volume near the top is 0.73L
Answer:
Explanation:
Hello,
In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:
In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:
Best regards.
Oxidation happens at the anode and reduction happens at the cathode.<span />
<span>The answer is hypertonic. In osmosis, water
molecules move from a hypotonic solution to the hypertonic solution, through a
semipermeable membrane. This occurs until
both solutions become isotonic relative to each other. In osmosis, only
the movement of water molecules occurs since the ions are large enough to pass
through the pores of the semipermeable membrane,
in this case, the cell membrane. Due to
loss of water in the process of osmosis, the cells in the fingers of the swimmers
shrunk hence looked shriveled.</span>
