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Daniel [21]
3 years ago
7

If 14c-labeled uracil is added to the growth medium of cells, what macromolecules will be labeled?

Chemistry
2 answers:
deff fn [24]3 years ago
8 0

If 14c-labeled uracil is added to the growth medium of cells, what macromolecules will be labeled? RNA

<h3>Further explanation </h3>

14C-labeled compounds

Specifications:

  • Specific Activity: 50-60 mCi/mmol 1.85-2.22 GBq/mmol
  • Synonym: Uracil [6-14C]
  • Formula: Not available
  • Molecular Weight: 112.1
  • Solvent: Sterile water
  • Concentration: 0.1 mCi/ml
  • CAS Number: Not available
  • Shipped in dry ice: No
  • Exclusive: Yes
  • Reference: Not available

If 14c-labeled uracil is added to the growth medium of cells, the macromolecules will be labeled Ribonucleic acid (RNA).

Ribonucleic acid (RNA) is a polymeric molecule essential in various biological roles in coding, decoding, regulation and expression of genes. RNA (ribonucleic acid) is made up of four chemical bases: adenine (A), cytosine (C), guanine (G) and uracil (U) connected by a ribose backbone. RNA is a single-stranded molecule and it is not stable under alkaline conditions. RNA directly codes for amino acids and as acts as a messenger between DNA and ribosomes to make proteins.

When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.

<h3>Learn more</h3>
  1. Learn more about RNA brainly.com/question/9091941

<h3>Answer details</h3>

Grade:  9

Subject:  chemistry

Chapter:  RNA

Keywords:  RNA

ziro4ka [17]3 years ago
6 0
When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.
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<h3>Further explanation</h3>

Condensation of steam through 2 stages:

1. phase change(steam to water)

2. cool down(100 to 0 C)

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Lv==latent heat of vaporization for water=2260 J/g

\tt Q=300\times 2260=678000~J

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<h3>What is bond energy?</h3>

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Learn more about bond energies: brainly.com/question/14842720?

7 0
1 year ago
A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

7 0
2 years ago
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