Answer:
8.7 mol Al
Explanation:
You have the compound Al₂Si₄O₁₀(OH)₂. Within the compound, you have atoms. You can tell how many atoms there are by looking at the subscript. You have 2 aluminum atoms, giving you 8.7 moles of aluminum.
4.35 × 2 = 8.7
the percent yield of the reaction is 100%.
The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:
% yield = actual yield / theoretical yield * 100%
% yield of a reaction in this case Rate
In this case, the molar mass of NaBr is 102.9 g / mol, as you know:
444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g
theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g
, Replaced by the definition of percent yield:
percent yield = 728.532 grams / 728.532 grams * 100%
percent yield = 100%
Finally, the percent yield of the reaction is 100%.
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FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.
Learn more about % yield here:brainly.com/question/27979178
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Answer:
≈ 708
Explanation
Here we have equation as:
4 Al + 3 O₂ → 2 Al₂O₃
As we know:
No of moles = Mass/ Molar mass
Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:
=375 g /27 g/mol
= 13.889 mol
About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.
As we know:
Mass= No of moles/Molar mass
Mass of Al₂O₃ = 6.944 mol × 102 g/mol
= 708.288 g
Hope it helps!
Answer :
0.125 g
Explanation : If you are calculating the half life of P-32 which has half life of 14.3 days and you want to calculate how many grams are remaining after 71.3 days if yo are starting with 4 g?
starting you can calculate the number of half life P-32 undergoes first,
which is n = 71.5 / 14.3 = 5 days.
now, to calculate the remaining mass,

=
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation: