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LenaWriter [7]
3 years ago
14

What is concentration of hydrogen ion a given acid if its PH value is 9?​

Chemistry
2 answers:
kifflom [539]3 years ago
8 0
PH = -log[H+], so [H+] = 10^-pH

[H+] = 1 • 10^-9 M
TEA [102]3 years ago
6 0
-log(9)= -0.954
______________
You might be interested in
How many moles of aluminum are in 4.35 moles of al2si4o10(OH)2
Gnoma [55]

Answer:

8.7 mol Al

Explanation:

You have the compound Al₂Si₄O₁₀(OH)₂.  Within the compound, you have atoms.  You can tell how many atoms there are by looking at the subscript.  You have 2 aluminum atoms, giving you 8.7 moles of aluminum.

4.35 × 2 = 8.7

6 0
4 years ago
The theoretical yield of NaBr from
Dvinal [7]

the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

<h3 />

FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

Learn more about % yield here:brainly.com/question/27979178

#SPJ10

5 0
2 years ago
Given:
strojnjashka [21]

Answer:

≈ 708

Explanation

Here we have equation as:

                        4 Al     +    3 O₂    →    2 Al₂O₃

As we know:  

                       No of moles = Mass/ Molar mass

Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:

                                            =375 g /27 g/mol

                                               =  13.889 mol

About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.

As we know:  

                            Mass= No of moles/Molar mass  

                      Mass of Al₂O₃ = 6.944 mol × 102  g/mol

                                           = 708.288 g

Hope it helps!

3 0
4 years ago
Phosphorus-32 has a half-life of 14.3 days. how many grams of phosphorus-32 remain after 71.5 days if you start with 4.00 grams?
almond37 [142]
Answer : 0.125 g

Explanation : If you are calculating the half life of P-32 which has half life of 14.3 days and you want to calculate how many grams are remaining after 71.3 days if yo are starting with 4 g?

starting you can calculate the number of half life P-32 undergoes first,

which is  n = 71.5 / 14.3 = 5 days.

now, to calculate the remaining mass,

m_{remaining}  = (\frac{initial mass}{2 X 2X 2X2 X2 } ) = (\frac{initial mass}{ 2^{5} } )

= = \frac{4 g }{ 2^{5} } = 0.125 g
7 0
3 years ago
Convert the following measurements using dimensional analysis. Set up problem using factors. Cross out the units that cancel. YO
uranmaximum [27]

Answer:

1) 0.423 m

2) 3.107 mi

3) 68.18 kg

4) 0.0083 mem

5) 0.528 gal

6) 4300 mL

7) 32.4 mem

8) 523.013 km

9) 70.866 in

10) 2.3 yek

Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.

Explanation:

4 0
3 years ago
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