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Nana76 [90]
3 years ago
13

Please help me I’m begging you please please please please please please please please please help me I’m begging you please hel

p me

Mathematics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

D

Step-by-step explanation

you are finding the area so you do the length( the dotted line) and the base(the bottom line)

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paul bought a soft and a sandwich for 9.90. what equation may be used to find the price of each item if the sandwich cost 3.5 ti
irina [24]

So, let's say the soft drink equals y and the sandwich equals x.

x + y = 9.9

The sandwich costs 3.5 times as much as the soft drink

x = 3.5y

Therefore, we can replace x with 3.5y since they're the same thing

3.5y + y = 9.9  <-- That's the equation :)


3 0
2 years ago
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =&#10;\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
3 years ago
Please help me! what’s the answer?<br><br> 1) Two points<br> 2) One point <br> 3) One equation
Fiesta28 [93]

Answer:

I think 2 points

Step-by-step explanation:

I may be wrong bc I suck at algebra. literally who is gonna use algebra ever?

4 0
2 years ago
Read 2 more answers
What is the standard form of the following equation:
Damm [24]

Answer:

My answer is D) y = 2(x - 2.5)^2 + 6

I hope it helps


7 0
2 years ago
Need Help
Fofino [41]

Answer:

$ 14.9

Step-by-step explanation:

we can create an equation

use variables:

pies = p

sauce = s

3.5p + 0.45s

3.5 (4) + 0.45(2)

<u>= $ 14.9</u>

3 0
3 years ago
Read 2 more answers
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