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egoroff_w [7]
3 years ago
12

What is the solution to the system of equations?​

Mathematics
1 answer:
Veronika [31]3 years ago
5 0

Answer: x = -2, y = 4

Step-by-step explanation:

Where the lines intersect on the graph.

X coordinate is x, Y coordinate is y.

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What is the slope of the line through (-9, 6) and (-3, 9)?<br> Choose 1 answer:
trasher [3.6K]

Given: Points (-9, 6) and (-3, 9)

Find:  The slope of the line that goes through those two points

Solution: In order to find the slope of the line that goes through the points that were provided we have to use the slope formula.  This formula subtracts the y-coordinates from each other and also the x-coordinates from each other to determine the rise/run which would give us the rate of change.

<u>Plug in the values</u>

  • m = \frac{y_2 - y_1}{x_2 - x_1}
  • m = \frac{9 - 6}{-3 - (-9)}

<u>Simplify the expression</u>

  • m = \frac{3}{-3 + 9}
  • m = \frac{3}{6}
  • m = \frac{1}{2}

Therefore, looking at the given options we can see that the best fitting one would be option A, 1/2.

4 0
1 year ago
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How would you write 62.22 in expanded form
BARSIC [14]
All you have to do is to solve this problem is 60+2+0.20+0.02
3 0
3 years ago
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Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

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Five increased by the product of a number and 9 is greater than -27<br> As an inequality
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Answer:

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A rectangular prism has a length of 5/2 ft, width of 9/6 ft, and height of 2/3 ft. what is its volume?
ivanzaharov [21]
The formula of the volume of the rectangular prism:

V = length × width × height

We have:
l=\dfrac{5}{2}ft\\\\w=\dfrac{9}{6}ft\\\\h=\dfrac{2}{3}ft\\\\V=l\cdot w\cdot h=\dfrac{5}{2}\cdot\dfrac{9}{6}\cdot\dfrac{2}{3}\\\\=\dfrac{5}{2}\cdot\dfrac{1}{1}\cdot\dfrac{1}{1}=\dfrac{5}{2}=2.5ft.^3
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3 years ago
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