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aniked [119]
3 years ago
9

A cylindrical water tank is being filled with a hose. The depth of the water increases by 1 1/4 feet per hour.

Mathematics
2 answers:
Elena L [17]3 years ago
6 0

Answer: 2 4/5

Your answer would be 2 4/5. Hope this helps.

Step-by-step explanation:

nirvana33 [79]3 years ago
3 0

Answer: 2\frac{4}{5} hours

Step-by-step explanation:

Given: The rate of increase of depth of water = 1\frac{1}{4}=\frac{5}{4} feet per hour.

Depth = 3\frac{1}{2}\ =\frac{7}{2}\ feet

Let h be the number of hours the water level in the tank to be 3\frac{1}{2} feet deep.

We know that the rate of change of depth of water with respect to time is given by :-

k=\frac{\text{Depth}}{\text{time}}\\\\\Rightarrow\ \frac{5}{4}=\frac{\frac{7}{2}}{h}\\\\\Rightarrow\ \frac{5}{4}=\frac{7}{2h}\\\\\Rightarrow5(2h)=4(7)\\\\\Rightarrow h=\frac{28}{10}=\frac{14}{5}=2\frac{4}{5}

Hence, it will take 2\frac{4}{5} hours for the water level in the tank to be 3\frac{1}{2} feet deep.

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Answer:

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Step-by-step explanation:

We have been given an equivalence equation x^2\equiv 53\text{ (mod } 77). We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

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