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Pie
3 years ago
8

Which of the following points must the graph of the linear equation y = 7x pass through to represent a direct variation?

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0
Is you substitute the x and y given in each of the points listed into the equation, the only correct answer is (0,0) or c
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Which pair of numbers is relatively prime? A. 102 and 321 B. 10 and 45 C. 3 and 51 D. 35 and 72
Natali [406]
Okay. I will list all the relatively prime numbers up to 331.
2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101, 103,107,109,113,127,131,137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331.
Okay, so look at this list and see which match up. 
For A. 102 and 312. Neither of these numbers are relatively prime.
For B. 10 and 45. Neither of these are relatively prime. 
For C. 3 and 51. 3 is a relatively prime number, 51 is not. 
For D. 35 and 72. Neither of these are relatively prime numbers.
But the answer would be D. because to get a relatively prime pair of numbers you have to have both of them not be divisible by the same number. 102 and 312 can be divided 2, so that's not the answer. 10 and 45 can be divided by 5, so that is incorrect. 3 and 51 can be divided by 3, so that is also incorrect. 35 and 72 cannot be divided by the same numbers. 
So, the answer is D. 35 and 72.
3 0
3 years ago
Read 2 more answers
The cost price of a box and a pen is Rs 80 The box is sold at 10% profit and the pen is sold at 20% loss. If the selling price o
uysha [10]

Answer:

61.84%

Step-by-step explanation:

Let the cost of the box be x. Since the price of the box and the pen is Rs 80, the pen's price can be represented as 80 - x. The box is sold at a ten percent profit, and an added ten percent is equal to 1.1. Therefore, the price the box sells at is 1.1(x). A 20% loss is the same a keeping 80% or multiplying by 0.8. This means the pen sold at 0.8(80 - x). Now, we are given the box went for Rs 28 more than the pen, so we can create an equation:

1.1x = 0.8(80 - x) + 28

We can simplify and solve:

1.1x = 64 - 0.8x + 28

1.9x = 92

x = 92/1.9

x = 920/19

The cost of the box after the increase would be 1.1(920/19) and the pen would be 0.8(80 - 920/19).

The sum of these two can be written as a percent x of 80.

80x = 0.8(80 - 920/19) + 1.1(920/19)

80x = 64 - 0.8(920/19) + 1.1(920/9)

80x = 64 - 0.3(920/19)

80x = 64 - 276/19

80x = 940/19

x = 940/1520

x = 0.6184

This is 61.84%

4 0
2 years ago
15.12 is what percent of 12?
Llana [10]

Answer:

<h2>126%</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\\begin{array}{ccc}15.12&-&p\%\\\\12&-&100\%\end{array}\qquad\text{cross multiply}\\\\\\12p=(15.12)(100)\\12p=1512\qquad\text{divide both sides by 12}\\p=126

\bold{METHOD\ 2}\\\\p\%=\dfrac{p}{100}\\\\p\%\ of\ 12\ is\ equal\ to\ 15.12:\\\\\dfrac{p}{100}\cdot12=15.12\\\\\dfrac{12p}{100}=15.12\qquad\text{multiply both sides by 100}\\\\12p=1512\qquad\text{divide both sides by 12}\\\\p=126

6 0
3 years ago
What is 12,140 X 4.0
kondor19780726 [428]

Answer: 48560

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?
Lina20 [59]
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\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right)  (xy+1)^2 = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  (xy+1)^2 = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0&#10;\\&#10;\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0&#10;\\&#10;\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0&#10;\\&#10;\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y&#10;&#10;
y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1&#10;\\&#10;\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}&#10;\\&#10;\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}&#10;\\&#10;\\y' = \frac{12 -12+3}{(6 -24-12-2 )}&#10;\\&#10;\\y' = \frac{3}{( -32 )}

7 0
3 years ago
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