Hello!
The equation would be y= -2/6x + (-3). Since, the y-intercept is -3 and the slope/growth is -2/6 (it's decreasing).
To find the slope just make a growth triangle. We go down twice (then to the right 6 times).
Hi there!

The value of f(-6) is the y-value at the x-coordinate x = -6.
Looking at the graph, we can see that at x = -6, y = 5.
Therefore, f(-6) = 5.
Answer:
Prospective study
Step-by-step explanation:
<em>A cross-sectional study, also known as transverse study, is a type of observational study that analyzes data from a population at a specific point in time.</em> This kind of observation is used if cases cannot be identified a priori or if the prevalence of the disease or condition needs to be determined.
Cohort studies are when two or more groups of subjects are followed over time to see if they develop some disease or if some event occurs, there are two type of cohort studies, prospective and retrospective. <em>Prospective studies (or follow-up studies) follow subjects with different exposures until some point in time where something happens or the study ends</em>, r<em>etrospective studies use historical data</em> to make comparisons based on risk factors or exposures that occurred before the events.
Considering the information given and the observational study exposed to the question, we can conclude that we are talking about a prospective study because data is collected over the next 10 years.
I hope you find this information useful and interesting! Good luck!
Scores are {72, 97, 82, x} where x is the unknown fourth score
They add up to 72+97+82+x = x+251
Divide this sum over four because there are four scores we want to average out. We end up with (x+251)/4 = M where M is the mean. Asa wants the mean to be 82, so make M = 82.
We can replace M with 82 and solve for x like so
(x+251)/4 = M
(x+251)/4 = 82
x+251 = 4*82
x+251 = 328
x = 328-251
x = 77
Asa needs a score of 77 on the fourth test so that the mean of the four tests is 82. If she scores higher than 77 on the fourth test, then the mean will be larger than 82.
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Depending on what your teacher is looking for, the first step is to establish your variable. So you would say "let x = fourth score". However, that seems too easy. So perhaps your teacher is looking for the equation (x+251)/4 = 82 or some variant of it.