Because the 18-gon is symmetrical, you can rotate it by 360/18 or 20 degrees. This is because when you rotate it by 20 degrees(to the left for explanation matters), any angle will now be in the position of its angle to its left.
The question is an illustration of equivalent equations.
<em>There are 11 units in all</em>
The given parameters are:
<u>Sage</u>



<u>Tristan</u>



Andre has twice of what Sage has
So, the total unit is:

<em>Sage has 2 units</em>
<em>Tristan has 5 units</em>
<em />
Because, Andre has twice of what <em>Sage has,</em>
Andre's number of units would be 4
So, we have:


Hence, there are 11 units in all
Read more about equivalent equations at:
brainly.com/question/18720297
Answer:

Step-by-step explanation:
Given


Required

This question is an illustration of binomial distribution where:

So, we have:


This gives


Expand




Answer: when Luis is on his his 10th week of lossing weigh and when roy is on his 9th week they will weigh the same
Step-by-step