You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer: The X intercept is located at (24,0) The Y intercept is located at (0,20)
The slope of the line represented by this equation is -5/6
Step-by-step explanation:
u19=-71.74
Step-by-step explanation:
u5=a+4d=-3.7....(1)
u15=a+14d=-52.3....(2)
-10d=48.6
d=-48.6/-10
d=-4.86
Substitute-4.86 into....(1)
u5=a+4(-4.86)=-3.7
a+(-19.44)=-4.7
a=-3.7-(-19.44)
a=15.74
19term=a+18d=?
=15.74+18(-4.86)
=15.74+(-87.48)
19th term =-71.74
Answer:
54.4
Step-by-step explanation:
Answer:
30.9
Step-by-step explanation:
8 + 10 + 8.9 + 4 = 30.9