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mart [117]
3 years ago
12

What is the distance between

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0

Answer:

The answer to your question is  \sqrt{65}

Step-by-step explanation:

Data

Point A = (-9, -6)

Point B = (-2, -2)

Process

To solve this problem, substitute the values in the equation.

Formula

dAB = \sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}

- Identify the values of x1, x2, y1 and y2

    x1 = -9  y1 = -6  x2 = -2  y2 = -2

-Substitution

dAB = \sqrt{(-2 + 9)^{2}+ (-2 + 6)^{2}}

-Simplification

dAB = \sqrt{7^{2} + 4^{2}}

dAB = \sqrt{49 + 16}

dAB = \sqrt{65}

ikadub [295]3 years ago
4 0
Coronavirus has resulted in humans speaking in tongues
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Scrat [10]

Answer:

the answer would be 1/225

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3 years ago
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Function number one , the graphing seems good
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The hypotenuse of a right triangle is twice the length of one of its legs. The length of the other leg is three feet. Find the l
aliya0001 [1]

a^2 + b^2 = c^2

Let c = hypotenuse = 2x

One of the legs = x. Let a or b = x.

I will let a = x. We can then say that b = 3.

3^2 + x^2 = (2x)^2

9 + x^2 = 4x^2

9 = 4x^2 - x^2

9 = 2x^2

9/2 = x^2

sqrt{9/2} = sqrt{x^2}

3/sqrt{2} = x

Rational denominator.

[3•sqrt{2}]/2 = x = a

Side 3 is given to be 3 feet. So, b = 3.

Hypotenuse = 2x

Hypotenuse = 2([3•sqrt{2}]/2)

Hypotenuse = 3•sqrt{2}

Understand?

The three sides are 3, [3•sqrt{2}]/2 and

3•sqrt{2}.

5 0
3 years ago
Which congruence postulate or theorem shows that the triangles below are congruent?
saul85 [17]

Answer:

A. AAS

Step-by-step explanation:

5 0
3 years ago
I need help with this question please
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Answer:

210 mph

Step-by-step explanation:

speed of jet = x

headwind: speed = x - 27

time taken = 1134.6/(x - 27)

tailwind: speed = x + 27

time taken = 1469.4/(x + 27)

same amount of time:

1134.6/(x - 27) = 1469.4/(x + 27)

Cross multiply,

1134.6(x + 27) = 1469.4(x - 27)

1134.6x + 30634.2 = 1469.4x - 39673.8

334.8x = 70308

x = 210 mph

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2 years ago
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