Mv^2 = const
<span>m ~ 1/v^2 </span>
<span>(4.5/10.1)^2 = 0.198 </span>
<span>20.2 * 0.198 = 4.0 g/mol (Helium)</span>
Answer:
M = 3.0 mol/L.
Explanation:
- We can calculate the molarity of a solution using the relation:
<em>M = (mass x 1000) / (molar mass x V)</em>
- M is the molarity "number of moles of solute per 1.0 L of the solution.
- mass is the mass of the solute (g) (m = 87.75 g of NaCl).
- molar mass of NaCl = 58.44 g/mol.
- V is the volume of the solution (ml) (V = 500.0 ml).
∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.
I think it’s A but I’m not sure. Sorry if I’m wrong
Given :
Moles of Na : 1.06
Moles of C : 0.528
Moles of O : 1.59
To Find :
The empirical formula of the compound.
Solution :
Dividing moles of each atom with the smallest one i.e 0.528 .
So,
Na : 1.06/0.528 = 2.007 ≈ 2
C : 0.528/0.528 = 1
O : 1.59/0.528 = 3.011 ≈ 3
Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.
So, empirical formula is
.
Hence, this is the required solution.
The process is called, Fixation