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Lelu [443]
3 years ago
14

Write a quadratic equation in standard form with the given roots of 3,-4

Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

Since the roots are 3, -4 then we must put

-3, 4 into this equation,

(x +a) * (x +b) = 0

(x -3) * (x +4) = 0 then multiplying

x^2 +x -12

Step-by-step explanation:

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Can some one help me please
krok68 [10]
16 feet= 192 inches
24 yards= 72 feet
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5 0
4 years ago
Solve log base(x − 1) 16 = 4.
vredina [299]
I hope this helps you


x=3

8 0
4 years ago
Read 2 more answers
Tell us whether the lines for each pair of equations are parallel, perpendicular, or neither:
Hatshy [7]
Two lines are parallel if the gradient (i.e. the x coefficient) of them both is the same.
Two lines are perpendicular if the gradient has its sign changed and has it's fraction flipped (i.e. a gradient of 2/3 would become -3/2, and a gradient of 10 would become -1/10)

THe first one is in the correct form already, with a gradient of -4.
Now we need to rearrange the second:-2x+8y=5 \\ 8y=2x+5 \\ y= \frac{2}{8} x+ \frac{5}{8} = \frac{1}{4}x+ \frac{5}{8}
The second equation has a gradient of 1/4, which is indeed the negative and reversal of -4, therefore the two lines are perpendicular.

3 0
4 years ago
Look at the figure. Complete the statement and justify your answer.VT=
egoroff_w [7]

Answer:

(C)

Step-by-step explanation:

From the given statement, \overline{VT} ≅\overline{VX} by the converse of the isosceles theorem as it states that if two angles are congruent in the triangle, then the two sides opposite to those equal angles will also be congruent that is \overline{VT} ≅\overline{VX}.

Hence, Option C is correct.

Rest of the options are not correct as the reflexive property states that any geometric figure, any angle or any line segment has same size and shape. NEither  \overline{VT} is equal to \overline{VX} nor \overline{TX} by reflexive property as the condition is not fulfiiled.

7 0
3 years ago
Read 2 more answers
24. Janet and Jack are walking in a two-day event to raise money for charity.
Serga [27]

Answer:

40 miles walk

Step-by-step explanation:

Let the miles walked by both of them be x at which money collected by same

for Janet

Fixed donation  asked = $7.50

money asked for walking 1 mile = $0.10

money made by Janet if he walks x miles = x*$0.10 = $0.10x

Total money collected by Janet = Fixed donation  asked + money made by Janet if he walks x miles

Total money collected by Janet =7.50 + 0.10x

For Jack

Fixed donation  asked = $5.50

money asked for walking 1 mile = $0.15

money made by Janet if he walks x miles = x*$0.15 = $0.15x

Total money collected by Jack = Fixed donation  asked + money made by Jack if he walks x miles

Total money collected by Jack =5.50 + 0.15x

we have to find miles at which money collected by both of them be same

and we have decided that it it as x mile walk then

Total money collected by Janet = Total money collected by Jack

7.50 + 0.10x = 5.50 + 0.15x

=> 7.50 - 5.50 = 0.15x - 0.10x

=> 2 = 0.05x

=> x = 2/0.05 = 40

Thus, at 40 miles walk money collected by both of them will be same

7 0
3 years ago
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