4/10 and 3/10 are the answers
Let's solve the first inequality at first. So,
−2(x + 4) + 10 < x − 7
-2x- 8 + 10 < x - 7 By distribution property.
-2x + 2 < x - 7 Adding the like terms.
-2x < x - 7 - 2 Subtract 2 from each sides.
-2x < x - 9 By simplifying.
-2x - x < -9 Subtract x from each sides.
-3x < -9
Since we are dividing by negative 3. So, sign of inequality will get change.
So, x>3
Now the next inequality is,
−2x + 9 > 3(x + 8)
-2x + 9 > 3x + 24
-2x > 3x + 24 - 9
-2x > 3x + 15
-2x - 3x > 15
-5x >15
So, x <-3
Hence, the correct choice is x > 3 or x < −3.
Answer:
The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.
Step-by-step explanation:
We're not sure what "system of equations" is being referenced here, since no equations are shown or described.
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Perhaps your "system of equations" is ...
f(x) = some equation
g(x) = some other equation
Then the solution to this system of equation is the pair of values (x, y) that gives ...
y = f(x) = g(x)
If x represents the month number, then the solution can be read from the table:
(x, y) = (2, 4)
This is the month in which exports and imports were equal. Both numbers were 4 in February.
30. find the unit rate of 183 miles in 3 hours
IF you want me to show the unit rate in miles per hour here is the method to do that:
=> 183 miles / 3 hours = 61 miles per hour.
Thus the unit rate is 61 miles per hour or 61 miles /h
Now, if you want to see the unit rate in miles per minute then here is the method to do that:
=> 1 hour = 60 minutes
=> 3 hours = 180 minutes
=> 183 miles / 180 minutes = 1.02 miles per minute
Answer:
$595
e) If the company insures a large number of these cars, they can expect the average cost per car to be approximately E(C).
Step-by-step explanation:
Given the distribution :
C $0 $500 $1000 $2,000
P(C) 0.60 0.05 0.13 0.22
Expected probability : E(C)
Σ[C * P(C)] = (0*0.60) + (500*0.05) + (1000*0.13) + (2000*0.22) = $595
Since the expected value could be interpreted as the average value of a random variable over a large Number of experiment or trials
