a. Answer: D: (∞, ∞)
R: (-∞, ∞)
<u>Step-by-step explanation:</u>
Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).
Theoretical range is the range of the equation given the domain.
c(p) = 25p
There are no restrictions on the p so the theoretical domain is All Real Numbers.
Multiplying 25 by All Real Numbers results in the range being All Real Numbers.
a) D: (∞, ∞)
R: (-∞, ∞)
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b. Answer: D: (0, 200)
R: (0, 5000)
<u>Step-by-step explanation:</u>
Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.
Practical range is the range of the equation given the practical values of the domain.
The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200
The range is 25p → (25)0 ≤ (25)p ≤ (25)200
→ 0 ≤ 25p ≤ 5000
b) D: (0, 200)
R: (0, 5000)
Answer:
The slope of the line is: 1
The y-intercept is: -3
You can graph the line using the slope and y-intercept, or two points.
Answer:
Line 1 is 1/3
Line 2 is 1/3 as well
Choice 1
Step-by-step explanation:
<u>Rise over run</u>
<em><u>Line 1:</u></em>


<u>Simplify:</u>
1/3
<em><u>Line 2:</u></em>


1/3
1 is Paralell to 2 because they have the same slope
I hope this helps! :D
Pls give thx and brainliest if i’m right!
Answer:
Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Step-by-step explanation:
✔️Function A:
Initial value = y-intercept (b)
y-intercept is the value of y, when the corresponding value of x = 0
From the table, y = 6 when x = 0.
The y-intercept of function A = 6
Therefore, initial value for Function A = 6
✔️Function B:
y = 4x + 3 is given in the slope-intercept form, y = mx + b.
b = y-intercept = initial value.
Therefore
Initial value for Function B = 3
✔️Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.