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diamong [38]
3 years ago
14

Jonathan and Tim want to predict how many quarters are in a large jar containing 120 coins. Jonathan randomly selects a sample o

f 10 coins from the jar, while Tim randomly selects a sample of 30 coins. Then they count the number of quarters in each sample. Whose sample should more accurately predict the number of quarters in the jar? sample should give a more accurate prediction of the number of quarters in the jar.
Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0


 the larger the sample the more accurate the prediction

 so since Tim looked at a larger quantity of coins his would be more accurate

kozerog [31]3 years ago
7 0
Tim would give a sample that should more accurately predict the numbers in the jar. He has taken out 1/4 of the coins from the jar.
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Perry made $20,000 per year.He soon he received a promotion(raise) with a 20% increase in pay.What is his new salary?How much is
user100 [1]
Hello! The salary goes up 20% due to the promotion. His original salary was $20,000. To find out his new salary, you have to do is multiply the original price by the rate. 20,000 * 20% (0.2) is 4,000. His promotion is $4,000. Now, we add. 20,000 + 4,000 is 24,000. There. Perry's new salary is $24,000.
5 0
3 years ago
Chris ran 25 miles, while Bill ran 5 miles. How many times farther did Chris run than Bill?
mixer [17]

Answer: Chris ran 20 miles more then Bill

Step-by-step explanation:

25(Chris) - 5(Bill) = 20 Miles

Hope this helped, have a great day/night!

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8 0
3 years ago
Read 2 more answers
Partial product of 1,262×3
Svetradugi [14.3K]

Answer:

3,786

Step-by-step explanation:

8 0
3 years ago
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
2 years ago
Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribu
kozerog [31]
Calculate the z-score for the given data points in the item using the equation,
 
                             z-score = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

Substituting,
             (47.7)     z-score = (47.7 - 52.5)/2.4 = -2

This translates to a percentile of 2.28%.

              (54.9)      z-score = (54.9 - 52.5)/2.4 = 1

This translates to a percentile of 84.13%. 

Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em> 

Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs. 
8 0
3 years ago
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