Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
I’m not positive, but I think the answer is C because when you look at the big triangle, it looks like you divide each coordinate by 3 (or multiply it by 1/3) to get the small triangle.
e.g. 6 * 1/3 = 2, 3 * 1/3 = 1
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Yuhh the answers c dawhggg trus me i just did the same thing lawl!
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im guessing the answer is 43.7
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E= -6
D= 4
B =- 4
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