Let:
v = Olga's speed
t = the time Anna spent going to school (3 km/hour)
t/2 = the time Anna spent running back home with speed of 6 km/hour
So, t + t/2 = 3t/2 is the total time
In the meantime distance = speed*time and the both made the same distance we can put it as:
3t + 6*(t/2) = (3t/2)*v
6t = (3/2)tv divide both sides by t
(3/2)v = 6
v = 2*6/3
v = 4 km/hour
Olga's speed was 4 km/hour.
That Equals = -60i. Hope im right :) Good luck
Answer:
A
c= s^3 AJ / km^2
Step-by-step explanation:
If you plug in this answer in the equation, you cancel out the km^2 and AJ, leaving s^3 = s^3
Answer:
∠1 - 40°
Step-by-step explanation:
∠1 - 40°
b/c it's a right triangle and we have two angles given, 50° and 90°. Add them and subtract by 180° and get 40°.
∠2 - 140°
b/c an exterior (outside) angle is equal to the two most isolated / farthest angles added. The two most is angles are 105° and 35°, add them and get 140°.
∠3 - 40°
b/c ∠'s 1 and 3 are vertical angles meaning they're equal so since ∠1 is 40°, so is ∠3.
∠4 -
b/c ∠' s 2 and 4 are vertical angles meaning they're equal so since ∠2 is 140°, so is ∠4.
∠5 - 35°
b/c we have two angles, 105° and 40°. Add them and subtract by 180° and get 35°.
hope that helps lol >:)
