3 years ago

4 3/10 as an improper fraction

Mathematics

1 answer:

alina1380 [7]3 years ago

8 0

Answer:

$\frac{43}{10}$

Step-by-step explanation:

$1 = \frac{1}{1}$

Hence,

$4 = \frac{4}{1}$

Multiply both numerator and denominator by 10:

$\frac{40}{10}$

Add 3/10 to get

$\frac{43}{10}$

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3/8 times 8/3 = 1
Answer=8/3

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Evelyn drinks 8 glasses of water,which is 56 glasses of water a week.How many glasses of water does she drink in a year?(1 year

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D%20%2B%20%5Csqrt%5B3%5D%7B0.027%7D%20-%20%5Csqrt%5B3%5D%7B125%7D" id="

e-lub [12.9K]

Step 1: calculate the cube roots, convert the decimal into a fraction, and calculate the cube roots again

10 + 3 square root 27/1000 - 5

Step 2: calculate the cube root

10 + 3/10 -5

Step 3: subtract the #’s

5 + 3/10

Step 4: calculate and you get

53/10

Answer: 53/10

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3 years ago

Help ASAP Please Thank You!

sasho [114]

Answer:

Step-by-step explanation:

$\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\frac{x^{12}}{x^{10}}=x^{12-10}=x^{2}$

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3 years ago

2x(squared) + 23x-19=0

Helen [10]

Use quadratic formula

for ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x= $\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x= $\frac{-23+/- \sqrt{529-152} }{4}$
x= $\frac{-23+/- \sqrt{377} }{4}$

x= $\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$

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4 years ago

4 3/10 as an improper fraction​

4 3/10 as an improper fraction