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VARVARA [1.3K]
3 years ago
11

4 3/10 as an improper fraction​

Mathematics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

\frac{43}{10}

Step-by-step explanation:

1 =  \frac{1}{1}

Hence,

4 =  \frac{4}{1}

Multiply both numerator and denominator by 10:

\frac{40}{10}

Add 3/10 to get

\frac{43}{10}

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If f(x)=x^5-1 g(x)=5x^2 and h(x)=2x which expression is equivalent to [g*f*h](9)
vagabundo [1.1K]
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x

Answer:
\underbrace{5(\underbrace{(\underbrace{2\cdot9}_{h(9)})^5-1}_{f(g(9))})^2}_{g(f(h(9)))}    \boxed{C.}
6 0
3 years ago
Which expressions of signed decimal numbers have negative quotients? Check all that apply.
dybincka [34]
A negative number divided by positive is a negative quotient and vice versa.
So
5.7 / -2.2
-0.01 / 0.05
Are the ones with negative quotients
7 0
3 years ago
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0.15, 0.17, 0.19.<br><br> what is going up by ?
Tpy6a [65]

Answer:

It goes up by 2 each time

Step-by-step explanation:

3 0
3 years ago
4(x+2)=4x+8 need help
alisha [4.7K]

Answer:

The answer is all real numbers

Step-by-step explanation:

4(x + 2) = 4x +8

Distribute the 4:

4x + 8 = 4x + 8

Then subtract 4x and 8 from both sides

0 = 0

This statement is true so its all real numbers

3 0
3 years ago
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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
andreyandreev [35.5K]
Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> <span>this is the starting equation
</span>

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

<span> Square root of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>

<span> Square root of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>


<span>Then, from here on all is wrong, but she made other additional mistakes.</span>

(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>

Later she made a mistake changing the sign of -8x to +8x


Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

3 0
3 years ago
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