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worty [1.4K]
3 years ago
6

Please help I’ll give brainiest!

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0

Answer: h(3)= -4 h(-3)=-16

Step-by-step explanation:

Plug in 3 and -3 for x and solve

h(3)= 2(3)-10

h(-3)= 2(-3)-10

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PLEASE HELP!!! HELP ME ANSWER A
olga nikolaevna [1]

Answer:

125,000 * 1.0625^t years

Step-by-step explanation:

compound interest = increase in amount

100 + 6.25 = 106.25

106.25/100 = 1.0625

therefore, 125,000 * 1.0625^years

6 0
2 years ago
3. the smallest number by which 168 must be multipled to get the perfect square number. ICA) 3 1(B)2 (c) 4 (o)5​
kaheart [24]

Answer:

42

Step-by-step explanation:

168 factors into

2•2•2•3•7

two of the 2's make a perfect square

(2•2)•2•3•7

   2²•2•3•7

as none of the product of the remaining factors makes a perfect square

2•3 = 6,  2•7 = 14,  3•7 = 21

we need to multiply the remaining factors together to find another perfect square

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2•3•7 = 42

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5 0
3 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
Consider the equation y = −6. Which statement is TRUE?
RideAnS [48]

y = 0x - 6     has a slope of 0

If you graph several points for x where y = -6,  <em>(0, -6), (1, -6), (2, -6), etc  </em>you will see that it creates a horizontal line

Answer: B

7 0
3 years ago
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