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PolarNik [594]
2 years ago
6

Find the value for x to the third decimal place: In x=5

Mathematics
1 answer:
mixas84 [53]2 years ago
8 0

\ln x=5\implies x=e^5\approx0.6738\cdot10^{-2}.

Hope this helps.

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Write 0.000 000 33 in scientific notation.
jarptica [38.1K]

<span>Number part = <span>3.3 </span></span>and

<span>Exponent part = -7</span>

<span>3.3*<span>10<span>−7</span></span></span>

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Eileen drove for 85 minutes. This is 21 more minutes than one third the number of minutes Ethan drove. How do I put this into an
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If 55% is 70.4 so what is hundred percent​
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2 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
2 years ago
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