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3 years ago

Estimate the difference 7 3/4 subtracted by 2 2/5 show your work

Mathematics

2 answers:

skad [1K]3 years ago

7 0

7 3/4 - 2 2/5
(7-2)+(3/4-2/5)
5+7/20

5 and 7/20 or 5.35

hodyreva [135]3 years ago

5 0

Answer:

5 7/20

Step-by-step explanation:

basically, you are going to want to turn these into improper fractions

7 3/4 = 28/4 + 3/4

= 31/4 (no further simplification)

2 2/5 = 10/5 + 2/5

= 12/5

now get common denominator to subtract

31/4 - 12/5

155/20 - 48/20 = 107/20

if you want this back into mixed fraction then convert

107/20 = 5 7/20

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Harvard University accepts 6 students for every 100 applicants. How many students will be accepted in 850 applicants apply for a

LenKa [72]

Answer:

51 students.

Step-by-step explanation:

First you need to establish a rate 6/100+3/50

8*100=800 6*8=48

3/50

850-800=50 3/50

48+3=51

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3 years ago

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fenix001 [56]

Answer:

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2 years ago

on the left side of the triangle, it says 10 cm, on the right side of the triangle, it says 18 cm, below the triangle, it says 1

stira [4]

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3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

Can anyone please help me with this? I don't know how to do it.

ycow [4]

Answer:

Step-by-step explanation:

The easiest way to fill out the graph is to find the slope.

The slope is y = 2x + 1.

Insert the x values of the graph for x in the equation to find y.

y = 2(-6) + 1 = -12 + 1 = -11. (-6, -11).

y = 2(-2) + 1 = -4 + 1= -3. (-2, -3).

Then, for finding x, just insert y.

1 = 2x + 1. Subtract 1 from both sides to isolate x.

0 = 2x. x = 0. (0, 1).

y = 2(2) + 1 = 4 + 1 = 5. (2, 5)

3 = 2x + 1. Subtract 1 from both sides.

2 = 2x. x = 1. (1, 3).

The slope of this function is 2x. The y-intercept is 1. The x-intercept is -2.

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3 years ago