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Ne4ueva [31]
3 years ago
8

Jerry ran 3/4 of a mile in 1/8 of an hour. What was Jerry's rate of speed in miles per hour?

Mathematics
2 answers:
omeli [17]3 years ago
6 0

The rate of speed of Jerry in miles per hour is 6 miles per hour

<u>Solution:</u>

Given that, Jerry ran 3/4 of a mile in 1/8 of an hour.  

<em><u>To find: </u></em>Jerry's rate of speed in miles per hour

The relation between distance and speed is given as:

\text { distance travelled }=\text { speed } \times \text { time taken }

\text { In our problem, distance travelled }=\frac{3}{4} \text { mile and time taken }=\frac{1}{8} \text { hour }

\begin{array}{l}{\rightarrow \text { speed }=\frac{\frac{3}{4}}{\frac{1}{8}}} \\\\ {\rightarrow \text { speed }=\frac{3}{4} \times \frac{8}{1}=6} \\\\ {\rightarrow \text { speed }=6 \text { miles per hour }}\end{array}

Hence, the speed of Jerry is 6 mile per hour.

yarga [219]3 years ago
3 0

Answer:

6 miles per hour

Step-by-step explanation:

we'll set up the problem like this:

3/4 mi = 1/8 hr

now multiply each side by 8:

24/4 mi = 1 hr

simplify:

6 mi = 1 hr

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Step-by-step explanation:

55-13=42

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2 years ago
Given a leading coefficient of 8, polynomial roots of 1 &amp; 2, and the known point on the graph (4,5). Write an equation that
m_a_m_a [10]

Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

y=a(x-c_1)(x-c_2)...(x-c_n)

Where, a is a constant and c_1,c_2,...,c_n are the roots of the polynomial.

Polynomial roots are 1 and 2. So, (x-1) and (x-2) are the factors of the polynomial.

Let the third root of the polynomial by c, then (x-c) is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

y=8(x-1)(x-2)(x-c)

The graph passes through the point (4,5). Putting x=4,y=5, we get

5=8(4-1)(4-2)(4-c)

5=8(3)(2)(4-c)

5=48(4-c)

Divide both sides by 48.

\dfrac{5}{48}=4-c

c=4-\dfrac{5}{48}

c=\dfrac{192-5}{48}

c=\dfrac{187}{48}

Therefore, the 3rd root on the polynomial is \dfrac{187}{48}.

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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
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