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2 years ago

9

HELP ASAP THIS IS STRESSING ME OUT!

1 answer:

Alex73 [517]2 years ago

6 0

The surface area of a right cylinder is the sum of the areas of the lateral face and the circular bases. The lateral face is really just a rectangle with the same height as the cylinder and a length equal to the circumference of the circular base.

If the radius of the base is $r$ and the height is $h$ , then the surface area of the cylinder is

$A=2\pi r^2+2\pi rh$

You're given that the area is $96\pi$ and the radius is $4$ , so you have

$96\pi=2\pi\times4^2+2\pi\times4h\implies 12=4+h\implies h=8$

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On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

Find the length of side BC. Round your answer to the nearest tenth.

Gwar [14]

Answer: 5.4

Step-by-step explanation:

8 0

2 years ago

An arrow on a spinner is spun 250 times. Some of the results are shown below. The relative frequency of landing on a 4 is the sa

N76 [4]

Answer:

11/50

Step-by-step explanation:

The frequency numbers for landing on 1, 2, and 3 are:

25, 53, 62.

We add them up to get: 25 + 53 + 62 = 140

Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then

250 - 140 = 110,

so 110 landed on 4 or 5.

We are told the numbers of spins landing on 4 and 5 are equal, so

110/2 = 55,

so the spinner landed 55 times on 4 and 55 times on 5.

relative frequency = 55/250 = 11/50

5 0

2 years ago

One eighth of the number of raisin bagels sold on Friday were sold on Saturday. How many raisin bagels were sold on Saturday? Th

Ivanshal [37]

Answer:

4

Step-by-step explanation:

I think the answer is 4, 1/8 of 32 is 4. I hope I'm right!!

4 Raisin Bagels were sold on Saturday.

7 0

2 years ago

Can anyone help please

harina [27]

The question mark is 5. 8-5=3 and 12-5=7

6 0

3 years ago