Answer:1968ft^2
Step-by-step explanation:
Perimeter(p)=178feet
P=2L+2w
178=2L+2w
178=2(L+w)
L+w=178 ➗ 2
L+w=89.............(1)
W+7=L
L-w=7...................(11)
L+w=89... ..........(1)
L-w=7...................(11)
Subtract (11) from (1)
2w=89-7
2w=82
w=82 ➗ 2
w=41 width=41feet
Substitute w=41 in (11)
L-w=7
L-41=7
L=7+41
L=48feet
Area= length x width
Area=48 x 41
Area=1968ft^2
Answer:
5.164×10^-5
Step-by-step explanation:
Answer:plz more info
Step-by-step explanation:do u have a pic of this question
Answer:
537 students
11 days
Step-by-step explanation:
5000
y= -----------------
(1+4999e^-0.8t)
a) after 8 days means t =8
5000
y= -----------------
(1+4999e^-0.8*8)
5000
y= -----------------
(1+4999e^-6.4)
5000
y= -----------------
(1+8.306)
5000
y= -----------------
(9.306)
y =537.28
Rounding to the nearest student
y = 537 students
b) 1/2 the student population means y =2500 (The 5000 is the student population)
5000
2500= -----------------
(1+4999e^-0.8t)
Multiply each side by (1+4999e^-0.8t)
2500 (1+4999e^-0.8t) = 5000
Divide each side by 2500
(1+4999e^-0.8t) = 5000/2500
(1+4999e^-0.8t) = 2
Subtract 1
(4999e^-0.8t) = 2-1
(4999e^-0.8t)=1
Divide by 4999
(4999/4999e^-0.8t)=1/4999
e^-0.8t=1/4999
Take the natural log of each side
ln(e^-0.8t)=ln(1/4999)
-.8t = ln(1/4999)
Divide by -.8
-.8/-8t = -1/.8 *ln(1/4999)
t = -1/.8 *ln(1/4999)
t≈10.6462
Rounding, it will take 11 days
2 less than1/3 idfk.......
