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rosijanka [135]
4 years ago
8

Find the area of the shaded regions round the hundredth if needed.

Mathematics
1 answer:
inn [45]4 years ago
7 0
1. Find the area of the circle. You know the radius = 10 in. Use
a = \pi {r }^{2}
2. Find the area of the (I'm assuming) equilateral triangle. Use the 30-60-90 rule to determine the length of half one of the edges, since you already know the hypotenuse of the 30-60-90 triangle. Multiply that value by 2 to get the length of one side. Then use
a = \frac{ \sqrt{3} }{4}  {l}^{2}
to find the area, where l = length of one side.

3. Subtract the area of the equilateral triangle from the area of the circle to find the area of the shaded region.

Hope this helps. Let me know if you're confused!
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John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
Write your answer in simplest radical form​
liubo4ka [24]

Answer:

x = 2 yd

Step-by-step explanation:

Angles of 45 degreees = two congruent legs

for the Pythagorean theorem

2x^2 = 8

x^2 = 4

x = 2

5 0
3 years ago
Read 2 more answers
12x+7&lt;−11 OR 5x−8&gt;40<br> solve for x
kipiarov [429]

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

x > 9.6

6 0
4 years ago
Read 2 more answers
Parallelogram PQRS has diagonals that are perpendicular. Based on that, which statement is most correct?
viva [34]

Answer:

B- Parallelogram PQRS is also a rhombus.

Step-by-step explanation:

Given

Parallelogram PQRS with perpendicular diagonals

Required

Which of the option is true

(a) PQRS can be a rectangle

A rectangle do not have perpendicular diagonals.

Hence, (a) is false

<em>If (a) is false, then (d) is also false</em>

(b) PQRS can a rhombus

The diagonals of a rhombus are not perpendicular.

So (b) <em>is true</em>

<em>No need to check for (c), since only option is true</em>

4 0
3 years ago
Read 2 more answers
In an RPG game, each player can choose among 5 basic classes: Mage, Warrior, Archers, Priests, Monks. Each basic class can advan
grigory [225]

Answer:

In RPGs a Character Class is a designation that determines a player's abilities and fighting style (and depending on the game possibly even their origin, education, and home area) often in the form of a job or archetype. A character class is defined by the abilities that it lends to a character — as such, two different characters with the same class are theoretically interchangeable, in that they have the same "power set" and can play the same role in gameplay because of their similar abilities. However, character class systems can come with varying levels of customization — ranging from characters of a given class being literally identical to having so much variety that character class is no longer even a good indicator of that character's abilities. While most common in fantasy Role-Playing Games, they have recently began to appear in other genres, such as trading card games and MOBAs.

Step-by-step explanation:

7 0
2 years ago
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